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PhD Thesis - Energy Systems Research Unit - University of Strathclyde

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Total <strong>Energy</strong> = Max x Fuel Used x Percentage (5.27)<br />

100<br />

where Total <strong>Energy</strong> = total useful energy available from partial load fuel use<br />

(kW)<br />

Max = maximum energy available from the fuel (kWh/kg)<br />

Fuel Used = partial load fuel use (kg/h)<br />

Percentage = percentage <strong>of</strong> energy available for use at 100% loading.<br />

The part <strong>of</strong> this total useful energy that is available as heat is the total amount<br />

minus the electrical output, and the heat to electricity ratio may then be<br />

calculated from these two figures. This whole process may be reduced to<br />

Equation 5.28.<br />

Ratiopart = SFCpart ( 1 + Ratio100% ) - 1 (5.28)<br />

SFC100%<br />

where Ratio100% = heat to electricity ratio at 100% load<br />

Ratiopart = heat to electricity ratio at partial load<br />

SFC100% = Specific Fuel Consumption at 100% load<br />

SFCpart = Specific Fuel Consumption at partial load<br />

If efficiency values are being used (gaseous fuels), the overall efficiency may be<br />

defined as<br />

Overall Efficiency = Efficiency x (Ratio + 1) (5.29)<br />

where Overall Efficiency = total heat and electrical efficiency<br />

Efficiency = electrical efficiency at 100% load<br />

Ratio = heat to electricity ratio at 100% load.<br />

Assuming the overall efficiency is constant, the heat to electricity ratio at partial<br />

load may be calculated using<br />

Ratiopart = (Overall Efficiency – Efficiencypart) (5.30)<br />

Efficiencypart<br />

136

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