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PhD Thesis - Energy Systems Research Unit - University of Strathclyde

PhD Thesis - Energy Systems Research Unit - University of Strathclyde

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with this new required engine power. This process is repeated continuously<br />

using the recalculated heat to power ratio to determine the required engine<br />

power in order to satisfy the heat demand, until the difference between the last<br />

calculated ratio and the current calculated ratio is plus or minus 0.0001. If the<br />

engine is following both heat and electricity demand, once the final heat to<br />

electricity ratio has been determined, it is necessary to check if it is still better to<br />

be following the heat demand rather than the electricity demand. Again, the<br />

required generator powers to meet either demand are determined, and whichever<br />

value is highest is used in Equation 5.22 to find the required engine power. The<br />

percentage load, specific fuel consumption or efficiency and heat to electricity<br />

ratio are then calculated as before.<br />

5.2.7 Actual Fuel Consumption<br />

Once the final values for the percentage load, specific fuel consumption or<br />

efficiency, heat to electricity ratio and number <strong>of</strong> engines running have been<br />

determined, it is necessary to calculate the actual fuel consumption required.<br />

This can be done using Equations 5.32 to 5.36. The equation used depends on<br />

the desired unit for the fuel (kWh for gas, litres for liquid and kg for solid fuels),<br />

and whether specific fuel consumption or efficiency values are being used.<br />

Although solid fuels may not be used in either <strong>of</strong> these types <strong>of</strong> engine, they<br />

may be used in Stirling engines, which will be considered later in this chapter.<br />

Consumption (litres) = SFC x Power (5.32)<br />

Density x Timesteps<br />

Consumption (litres) = 3610.3 x 100 x 1000 x Power (5.33)<br />

Efficiency x CV x Density x Timesteps<br />

Consumption (kg) = SFC x Power (5.34)<br />

1000 x Timesteps<br />

Consumption (kg) = 3610.3 x 100 x Power (5.35)<br />

Efficiency x CV x Timesteps<br />

Consumption (kWh) = 100 x Power (5.36)<br />

Efficiency x Timesteps<br />

140

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