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PhD Thesis - Energy Systems Research Unit - University of Strathclyde

PhD Thesis - Energy Systems Research Unit - University of Strathclyde

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number <strong>of</strong> timesteps per hour. From these, the amount <strong>of</strong> hydrogen that can<br />

actually be made, and the percentage load this would require, can be determined<br />

using Equations 5.41 and 5.42.<br />

Can Make = Electricity (5.41)<br />

Consumption + Storage<br />

Percentage Load = 100 x Can Make (5.42)<br />

Maximum<br />

Where Can Make = Amount <strong>of</strong> hydrogen which can be made with the<br />

available electricity (Nm 3 )<br />

Electricity = Electricity available over that timestep (kWh)<br />

Consumption = Electricity consumption at 100% load (kWh/Nm 3 )<br />

Storage = <strong>Energy</strong> required to put hydrogen into storage (kWh/Nm 3 )<br />

Maximum = Maximum amount <strong>of</strong> hydrogen that may be made during<br />

the timestep (Nm 3 )<br />

If the percentage load is less than the stated minimum load, the electrolyser is<br />

not run. If the percentage load is greater than 100%, the electrolyser is run at<br />

full load, and the electricity used, hydrogen made, and water used are calculated<br />

using Equations 5.43, 5.44 and 5.45.<br />

Electricity Used (kW) = Consumption x Maximum x Time (5.43)<br />

Hydrogen Made (kWh) = Maximum x 3 (5.44)<br />

Water Used (litres) = Water x Maximum (5.45)<br />

Where Time = Number <strong>of</strong> timesteps per hour<br />

Water = Water required (litre/Nm 3 )<br />

1 Nm 3 <strong>of</strong> hydrogen = 3 kWh<br />

If the percentage load is between minimum and maximum load, it is necessary<br />

to recalculate the amount <strong>of</strong> hydrogen that may be made (using the power<br />

consumption figure for the percentage load just calculated). This is because the<br />

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