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an investigation of dual stator winding induction machines

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When the estimated rotor speed is used as feedback, the tr<strong>an</strong>sfer function between the<br />

reference speed <strong>an</strong>d the rotor speed is defined as:<br />

* ( ω − ˆ ω )<br />

( )<br />

( ) ⎟ p ⎞<br />

p<br />

⎛ * Ai<br />

pω = ⋅ = ⋅<br />

⎜<br />

r Kω<br />

r r K ωr<br />

− ω<br />

⎝ Bi<br />

⎠<br />

σ ω = ω<br />

r<br />

ω<br />

ω<br />

Kω<br />

Bi<br />

( p)<br />

( p)<br />

+ K A ( p)<br />

r =<br />

(10.148)<br />

*<br />

r pBi<br />

ω i<br />

A PI controller is adopted in (10.148),<br />

kwi<br />

Kω<br />

= kwp<br />

+<br />

(10.149)<br />

S<br />

Substituting (10.149) into (10.148), the tr<strong>an</strong>sfer function <strong>of</strong> the speed controller<br />

becomes:<br />

ω<br />

ω<br />

=<br />

r<br />

*<br />

r<br />

p<br />

+<br />

( pkωp<br />

+ kωi<br />

) Bi<br />

( p)<br />

= 2<br />

p Bi<br />

( p)<br />

+ ( pkωp<br />

+ kωi<br />

) Ai<br />

( p)<br />

5<br />

4<br />

3<br />

kωp<br />

A4i<br />

p + ( kωp<br />

A3i<br />

+ kωi<br />

A4i<br />

) p + ( kωp<br />

A2i<br />

+ kωi<br />

A3i<br />

) p<br />

2<br />

+ ( kωp<br />

A1i<br />

+ kωi<br />

A2i<br />

) p + ( kωp<br />

A0i<br />

+ kωi<br />

A1i<br />

) p + kωi<br />

A0i<br />

7<br />

6<br />

5<br />

4<br />

+ B4i<br />

p + ( B3i<br />

+ kωp<br />

A4i<br />

) p + ( B2i<br />

+ kωp<br />

A3i<br />

+ kωi<br />

A4i<br />

) p<br />

3<br />

2<br />

( B1i<br />

+ kωp<br />

A2i<br />

+ kωi<br />

A3i<br />

) p + ( B0i<br />

+ kωp<br />

A1i<br />

+ kωi<br />

A2i<br />

) p + ( kωp<br />

A0i<br />

+ kωi<br />

A1i<br />

) p + kωi<br />

A0i<br />

The D-decomposition method is used to plot the boundary <strong>of</strong> the stable region,<br />

−<br />

−<br />

408<br />

(10.150)<br />

7<br />

6<br />

5<br />

4<br />

jω0<br />

− B4iω0<br />

+ j(<br />

B3i<br />

+ kωp<br />

A4i<br />

) ω0<br />

+ ( B2i<br />

+ kωp<br />

A3i<br />

+ kωi<br />

A4i<br />

) ω0<br />

− j(<br />

B1i<br />

+ kωp<br />

A2i<br />

+ kωi<br />

A3i<br />

)<br />

2<br />

( B + k A + k A ) ω + j(<br />

k A + k A ) ω + k A = 0<br />

0i<br />

ωp<br />

1i<br />

ωi<br />

2i<br />

0<br />

Separating (10.151) into imaginary <strong>an</strong>d real parts, then<br />

6<br />

⎪⎧<br />

− B4iω0<br />

⎨ 6<br />

⎪⎩ − ω0<br />

+<br />

ωp<br />

0i<br />

ωi<br />

4<br />

2<br />

+ ( B2i<br />

+ kωp<br />

A3i<br />

+ kωi<br />

A4i<br />

) ω0<br />

− ( B0i<br />

+ kωp<br />

A1i<br />

+ kωi<br />

A2i<br />

) ω0<br />

+ kωi<br />

A0i<br />

4<br />

2<br />

( B + k A ) ω − ( B + k A + k A ) ω + ( k A + k A )<br />

3i<br />

ωp<br />

4i<br />

0<br />

1i<br />

ωp<br />

2i<br />

1i<br />

ωi<br />

0<br />

3i<br />

0<br />

ωi<br />

0i<br />

ωp<br />

0i<br />

ωi<br />

1i<br />

= 0<br />

= 0<br />

(10.151)<br />

(10.152)<br />

ω<br />

3<br />

0

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