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an investigation of dual stator winding induction machines

an investigation of dual stator winding induction machines

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k<br />

cs<br />

τ s<br />

=<br />

2<br />

2b<br />

⎪<br />

⎧<br />

⎡ ⎤⎪<br />

⎫<br />

0 b0<br />

g ⎛ b0<br />

⎞<br />

τ s − ⎨a<br />

t<strong>an</strong> − log⎢1<br />

+ ⎜ ⎟ ⎥⎬<br />

π ⎪⎩<br />

2g<br />

b0<br />

⎢⎣<br />

⎝ 2g<br />

⎠ ⎥⎦<br />

⎪⎭<br />

The <strong>stator</strong> slot opening b 0.<br />

0027 m<br />

k cs<br />

=<br />

0.<br />

0111<br />

= 1.<br />

179<br />

−<br />

0.<br />

0054<br />

π<br />

0 = . From which<br />

0.<br />

0174<br />

2<br />

⎪⎧<br />

0.<br />

0027 0.<br />

00033 ⎡ ⎛ 0.<br />

0027 ⎞ ⎤⎪⎫<br />

⎨a<br />

t<strong>an</strong> − log⎢1<br />

+ ⎜ ⎟ ⎥⎬<br />

⎪⎩<br />

0.<br />

00066 0.<br />

0027 ⎢⎣<br />

⎝ 0.<br />

00066 ⎠ ⎥⎦<br />

⎪⎭<br />

59<br />

(2.29)<br />

Since the rotor slot is chosen to be closed type, the carter's coefficient for the rotor<br />

slots is:<br />

k cr = 1.<br />

0<br />

The effective air gap is therefore<br />

ge = kcsk<br />

crl<br />

g<br />

= 1.<br />

179⋅1.<br />

0⋅<br />

0.<br />

33<br />

= 0.<br />

389 mm<br />

The amplitude <strong>of</strong> flux density at the point 30 o away from the maximum is:<br />

B o<br />

g 2(<br />

30 ) =<br />

3<br />

Bg<br />

2<br />

2<br />

= 0.<br />

866⋅<br />

0.<br />

16<br />

=<br />

0.<br />

139<br />

T<br />

Therefore, the MMF required to overcome the air gap is given as:<br />

= 42.<br />

9 At<br />

(2.30)<br />

(2.31)<br />

B o<br />

g 2(<br />

30 )<br />

F o = g<br />

g ( 30 )<br />

e<br />

µ (2.32)<br />

0<br />

B) MMF <strong>of</strong> <strong>stator</strong> tooth F ts<br />

The tooth width at the top is given as

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