13.10.2012 Views

boylistad

boylistad

boylistad

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

1054 ⏐⏐⏐ DECIBELS, FILTERS, AND BODE PLOTS<br />

dB<br />

Fig. 23.57(c) we are plotting Av versus the maximum value of Av. On<br />

most data sheets and for the majority of the investigative techniques<br />

commonly employed, the normalized plot of Fig. 23.57(c) is used<br />

because it establishes 0 dB as an asymptote for the dB plot. To ensure<br />

that the impact of using either Fig. 23.57(b) or Fig. 23.57(c) in a frequency<br />

plot is understood, the analysis of the filter of Fig. 23.55 will<br />

include the resulting dB plot for both normalized curves.<br />

For the network of Fig. 23.55:<br />

Vo � �R2� �V R2Vi 1<br />

�� �� i<br />

R1 � R2 � jXC R1 � R2 � jXC Dividing the top and bottom of the equation by R1 � R2 results in<br />

R2 1<br />

Vo ��<br />

——<br />

R1 � R2 XC<br />

�1 � j��� R1 � R2 XC 1<br />

1<br />

but �j� ��j�� ��j��<br />

R1 � R2 q(R1 � R2)C 2pf(R1 � R2)C fc 1<br />

��j� with fc �� and RTh � R1 � R2 f<br />

2pRThC<br />

so that Vo � � �V �� i<br />

If we divide both sides by V i, we obtain<br />

Vo �<br />

Vi<br />

R 2<br />

� R1 � R 2<br />

A v � � � � (23.41)<br />

from which the magnitude plot of Fig. 23.57(b) can be obtained. If we<br />

divide both sides by A vmax � R 2/(R 1 � R 2), we have<br />

(23.42)<br />

from which the magnitude plot of Fig. 23.57(c) can be obtained.<br />

Based on the past section, a dB plot of the magnitude of A′ v �<br />

Av/Avmax is now quite direct using Fig. 23.54(b). The plot appears in Fig.<br />

23.58.<br />

For the gain Av � Vo/Vi, we can apply Eq. (23.5):<br />

20 log10 ab � 20 log10 a � 20 log10 b<br />

where<br />

R2 1<br />

20 log10� ����� R2 1<br />

� ��<br />

R1 � R2 1� j( fc/f )<br />

A� Av<br />

1<br />

v � �� � �<br />

A 1 � j(<br />

fc/f )<br />

�<br />

vmax<br />

1<br />

� 20 log10 � 20 log10 ��<br />

�1� ��(�fc�/f�)<br />

The second term will result in the same plot of Fig. 23.58, but the<br />

first term must be added to the second to obtain the total dB response.<br />

Since R2/(R1 � R2) must always be less than 1, we can rewrite the<br />

first term as<br />

R2 1<br />

R<br />

20 log 1 � R<br />

10 � 20 log 2<br />

R1 � R 10 � 20 log<br />

2 R1 � R 101 � 20 log10 2<br />

R2 0<br />

2<br />

�<br />

R1 � R2 1 � j( fc/f )<br />

R2 �<br />

R1 � R2 �<br />

R 2<br />

1<br />

1� j( fc/f )

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!