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550 ⏐⏐⏐ SINUSOIDAL ALTERNATING WAVEFORMS<br />

40<br />

0<br />

–40<br />

1600<br />

0<br />

v (V)<br />

v 2 (V)<br />

10 20 t (ms)<br />

1 cycle<br />

FIG. 13.59<br />

Example 13.23.<br />

10<br />

20<br />

t (ms)<br />

FIG. 13.60<br />

The squared waveform of Fig. 13.59.<br />

EXAMPLE 13.23 Determine the average and rms values of the square<br />

wave of Fig. 13.59.<br />

Solution: By inspection, the average value is zero.<br />

v 2 (Fig. 13.60):<br />

(1600)(10 � 10 �3 ) � (1600)(10 � 10 �3 )<br />

�����<br />

20 � 10 �3<br />

V rms � ����<br />

32,000 � 10<br />

� � �1�6�0�0� �� �3<br />

���3<br />

20 � 10<br />

Vrms � 40 V<br />

(the maximum value of the waveform of Fig. 13.60)<br />

The waveforms appearing in these examples are the same as those<br />

used in the examples on the average value. It might prove interesting to<br />

compare the rms and average values of these waveforms.<br />

The rms values of sinusoidal quantities such as voltage or current<br />

will be represented by E and I. These symbols are the same as those<br />

used for dc voltages and currents. To avoid confusion, the peak value<br />

of a waveform will always have a subscript m associated with it: I m<br />

sin qt. Caution: When finding the rms value of the positive pulse of a<br />

sine wave, note that the squared area is not simply (2A m) 2 � 4A 2 m;it<br />

must be found by a completely new integration. This will always be<br />

the case for any waveform that is not rectangular.<br />

A unique situation arises if a waveform has both a dc and an ac component<br />

that may be due to a source such as the one in Fig. 13.61. The<br />

combination appears frequently in the analysis of electronic networks<br />

where both dc and ac levels are present in the same system.<br />

+<br />

3 sin ωt<br />

–<br />

6 V<br />

+<br />

v T<br />

–<br />

7.5 V<br />

6 V<br />

4.5 V<br />

v T<br />

0 t<br />

FIG. 13.61<br />

Generation and display of a waveform having a dc and an ac component.<br />

The question arises, What is the rms value of the voltage vT? One<br />

might be tempted to simply assume that it is the sum of the rms values<br />

of each component of the waveform; that is, VT � 0.7071(1.5 V) �<br />

rms<br />

6 V � 1.06 V � 6 V � 7.06 V. However, the rms value is actually<br />

determined by<br />

Vrms � �V� 2 �dc �� V� 2 ac� (rm� s) � (13.37)<br />

which for the above example is<br />

Vrms � �(6� V�) 2 � �� (�1�.0�6� V�) 2 �<br />

� �3�7�.1�2�4� V<br />

� 6.1 V

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