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324 ⏐⏐⏐ NETWORK THEOREMS<br />

+<br />

E1– 54 V R 2 12 �<br />

R 1<br />

24 �<br />

R 1<br />

24 �<br />

R 2<br />

54-V battery replaced<br />

by short circuit<br />

12 �<br />

R 3<br />

4 �<br />

I″ 3<br />

E 2<br />

EXAMPLE 9.2 Using superposition, determine the current through<br />

the 4-� resistor of Fig. 9.6. Note that this is a two-source network of<br />

the type considered in Chapter 8.<br />

FIG. 9.6<br />

Example 9.2.<br />

Solution: Considering the effects of a 54-V source (Fig. 9.7):<br />

RT � R1 � R2 �� R3 � 24 ��12 � �� 4 ��24 ��3 ��27 �<br />

E1 54 V<br />

I �����2 A<br />

RT 27 �<br />

I� 3<br />

+<br />

48 V<br />

–<br />

48-V battery<br />

replaced by short<br />

circuit<br />

R 1<br />

E 1<br />

24 �<br />

R T<br />

FIG. 9.8<br />

The effect of E 2 on the current I 3.<br />

+<br />

–<br />

I<br />

R 1<br />

24 �<br />

+<br />

E1 –<br />

54 V R2 12 �<br />

4 �<br />

54 V<br />

8 �<br />

R 1<br />

24 �<br />

R 2<br />

R 2<br />

R 3<br />

12 �<br />

12 �<br />

E 2<br />

I 3<br />

I″ 3<br />

RT R 3<br />

4 �<br />

E 2<br />

+<br />

48 V<br />

–<br />

R3 = 4 �<br />

3 �<br />

FIG. 9.7<br />

The effect of E1 on the current I3. Using the current divider rule,<br />

R2I (12 �)(2 A) 24 A<br />

I′ 3 ����� ���1.5 A<br />

R2 � R3 12 ��4 � 16<br />

Considering the effects of the 48-V source (Fig. 9.8):<br />

RT � R3 � R1 �� R2 � 4 ��24 � �� 12 ��4 ��8 ��12 �<br />

E2 48 V<br />

I″ 3 �����4 A<br />

RT 12 �<br />

R 3<br />

I� 3<br />

4 �<br />

+<br />

48 V<br />

–<br />

Th

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