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288 ⏐⏐⏐ METHODS OF ANALYSIS AND SELECTED TOPICS (dc)<br />

EXAMPLE 8.24 Find the voltage across the 3-� resistor of Fig. 8.55<br />

by nodal analysis.<br />

4 A<br />

+<br />

8 V<br />

–<br />

2 �<br />

V 1<br />

2 �<br />

6 � 10 �<br />

+<br />

4 � V3� 3 � 1 V<br />

–<br />

FIG. 8.55<br />

Example 8.24.<br />

Solution: Converting sources and choosing nodes (Fig. 8.56), we<br />

have<br />

resulting in<br />

and<br />

6 �<br />

4 � V3� 3 �<br />

FIG. 8.56<br />

Defining the nodes for the network of Fig. 8.55.<br />

+<br />

–<br />

V 2<br />

Reference<br />

10 �<br />

� � � �V 1 1 1 1<br />

� � � 1 � � � �V2��4 A<br />

2 � 4 � 6 � 6 �<br />

� � � �V 1 1 1 1<br />

� � � 2 � � � �V1��0.1 A<br />

10 � 3 � 6 � 6 �<br />

11 1<br />

�V1 � �V2 � 4<br />

12 6<br />

1 3<br />

��V1 � �V2 ��0.1<br />

6 5<br />

11V 1 � 2V 2 ��48<br />

�5V 1 � 18V 2 ��3<br />

⎫<br />

⎪<br />

⎬<br />

⎪<br />

⎪<br />

⎭<br />

–<br />

+<br />

0.1 A<br />

� 11 48�<br />

��5 �3� �33 � 240 207<br />

V 2 � V 3� � ––––––––– � –––––––––– � –––– � 1.101 V<br />

� 11 �2� 198 � 10 188<br />

��5 18�<br />

As demonstrated for mesh analysis, nodal analysis can also be a very<br />

useful technique for solving networks with only one source.<br />

N A

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