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P<br />

and (R 1 � R 2)I 1 � R 2I<br />

R 1I 1 � R 2I 1 � R 2I<br />

R 1I 1 � R 2I � R 2I 1<br />

Substituting values:<br />

R 1 �<br />

R1 �� R2(I � I<br />

�<br />

1)<br />

I<br />

6 42 �<br />

� 7 ���� 21�<br />

���2 �<br />

21<br />

An alternative approach is<br />

I2 � I � I1 (Kirchhoff’s current law)<br />

� 27 mA � 21 mA � 6 mA<br />

V2 � I2R2 � (6 mA)(7 �) � 42 mV<br />

V1 � I1R1 � V2 � 42 mV<br />

42 mV<br />

and R1 �����2 �<br />

I1 21 mA<br />

V 1<br />

From the examples just described, note the following:<br />

Current seeks the path of least resistance.<br />

That is,<br />

1. More current passes through the smaller of two parallel resistors.<br />

2. The current entering any number of parallel resistors divides into<br />

these resistors as the inverse ratio of their ohmic values. This relationship<br />

is depicted in Fig. 6.39.<br />

I 1<br />

I<br />

4 � 4 �<br />

I<br />

I 1 = I<br />

2<br />

I 1<br />

7 �(27 mA � 21 mA)<br />

���<br />

21 mA<br />

2I 1<br />

1<br />

I<br />

I 1<br />

1 � 2 �<br />

I<br />

I 1 = I<br />

3<br />

6.7 VOLTAGE SOURCES IN PARALLEL<br />

3I 1<br />

I<br />

2 � 6 �<br />

I<br />

I 1 = I<br />

4<br />

FIG. 6.39<br />

Current division through parallel branches.<br />

Voltage sources are placed in parallel as shown in Fig. 6.40 only if they<br />

have the same voltage rating. The primary reason for placing two or<br />

more batteries in parallel of the same terminal voltage would be to<br />

VOLTAGE SOURCES IN PARALLEL ⏐⏐⏐ 187<br />

I 1<br />

6I 1<br />

I<br />

2I 1<br />

1 � 3 �<br />

I<br />

I 1 = I<br />

9<br />

I 1<br />

6 �

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