13.10.2012 Views

boylistad

boylistad

boylistad

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

662 ⏐⏐⏐ SERIES AND PARALLEL ac CIRCUITS<br />

or, finally,<br />

PT � PR � PL � EIR cos vR � EIL cos vL � (20 V)(6 A) cos 0° � (20 V)(8 A) cos 90° � 120 W � 0<br />

� 120 W<br />

Power factor: The power factor of the circuit is<br />

Fp � cos vT � cos 53.13° � 0.6 lagging<br />

or, through an analysis similar to that employed for a series ac circuit,<br />

E EG G G<br />

cos vT � � ������ I I/V YT<br />

2 P /R<br />

� �<br />

EI EI<br />

G<br />

and Fp � cos vT � �� (15.32)<br />

Y<br />

where G and YT are the magnitudes of the total conductance and admittance<br />

of the parallel network. For this case,<br />

0.3 S<br />

Fp � cos vT ���0.6 lagging<br />

0.5 S<br />

Impedance approach: The current I can also be found by first finding<br />

the total impedance of the network:<br />

Z<br />

ZT �<br />

RZL (3.33 � �0°)(2.5 � �90°)<br />

� ����<br />

ZR � ZL 3.33 � �0° � 2.5 � �90°<br />

8.325 �90°<br />

��� �2 � �53.13°<br />

4.164 �36.87°<br />

And then, using Ohm’s law, we obtain<br />

E 20 V �53.13°<br />

I ����� �10 A �0°<br />

ZT 2 � �53.13°<br />

R-C<br />

Refer to Fig. 15.66.<br />

i = 14.14 sin qt<br />

+<br />

e<br />

–<br />

iR<br />

T<br />

R 1.67 �<br />

FIG. 15.66<br />

Parallel R-C network.<br />

Phasor Notation As shown in Fig. 15.67.<br />

Y T and Z T<br />

a<br />

X C<br />

i C<br />

1.25 �<br />

1<br />

1<br />

YT � YR � YC � G �0° � BC �90° �� �0° �� �90°<br />

1.67 �<br />

1.25 �<br />

� 0.6 S �0° � 0.8 S �90° � 0.6 S � j 0.8 S � 1.0 S �53.13°<br />

1 1<br />

ZT ����� �1 � ��53.13°<br />

YT 1.0 S�53.13°<br />

a c

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!