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1 Introduction 1.1 THE ELECTRICAL/E
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� S I mind that similar progressi
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� S I denser, which we refer to t
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� S I decades will probably conta
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� S I TABLE 1.1 Comparison of the
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� S I The second was originally d
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� S I A quick method of determini
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� S I revealing that the operatio
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� S I 1 1 2300 � � 3.333E�1
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� S I Since the power of ten will
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� S I EXAMPLE 1.14 a. Determine t
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� S I Initial Settings Format and
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� S I c. Since the division will
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� S I Three software packages wil
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� S I SECTION 1.8 Conversion with
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2 Current and Voltage 2.1 ATOMS AND
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I e V CURRENT ⏐⏐⏐ 33 the dist
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I e V The chemical activity of the
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I e V erence plane. If the weight i
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I e V 2.4 FIXED (dc) SUPPLIES The t
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I e V FIG. 2.14 Maintenance-free 12
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I e V batteries are relatively warm
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I e V EXAMPLE 2.5 a. Determine the
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I e V TABLE 2.1 Relative conductivi
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I e V be accomplished is to open th
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I e V (a) (c) Contact Sliding switc
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I e V Control switch Meter leads (a
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I e V tant to disconnect the charge
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I e V GLOSSARY ⏐⏐⏐ 57 28. Fin
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3 Resistance 3.1 INTRODUCTION The f
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R G Note that the area of the condu
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R G EXAMPLE 3.3 What is the resista
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R G RESISTANCE: METRIC UNITS ⏐⏐
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R G The conversion factor between r
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R G Absolute zero -273.15°C Inferr
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R G Since R 20 of Eq. (3.8) is the
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R G result is a tremendous saving i
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R G TYPES OF RESISTORS ⏐⏐⏐ 75
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R G TYPES OF RESISTORS ⏐⏐⏐ 77
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R G a 1% failure rate would reveal
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R G gaps. Dropping to the 10% level
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R G THERMISTORS ⏐⏐⏐ 83 Prelim
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R G APPLICATIONS ⏐⏐⏐ 85 3.14
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R G longer heating element in stand
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R G cally this law relates voltage,
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R G MATHCAD ⏐⏐⏐ 91 key at the
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R G *13. What is the new resistance
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R G SECTION 3.13 Varistors 58. a. R
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98 ⏐⏐⏐ OHM’S LAW, POWER, AN
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100 ⏐⏐⏐ OHM’S LAW, POWER, A
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102 ⏐⏐⏐ OHM’S LAW, POWER, A
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104 ⏐⏐⏐ OHM’S LAW, POWER, A
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106 ⏐⏐⏐ OHM’S LAW, POWER, A
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108 ⏐⏐⏐ OHM’S LAW, POWER, A
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110 ⏐⏐⏐ OHM’S LAW, POWER, A
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112 ⏐⏐⏐ OHM’S LAW, POWER, A
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114 ⏐⏐⏐ OHM’S LAW, POWER, A
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116 ⏐⏐⏐ OHM’S LAW, POWER, A
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118 ⏐⏐⏐ OHM’S LAW, POWER, A
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120 ⏐⏐⏐ OHM’S LAW, POWER, A
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122 ⏐⏐⏐ OHM’S LAW, POWER, A
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124 ⏐⏐⏐ OHM’S LAW, POWER, A
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126 ⏐⏐⏐ OHM’S LAW, POWER, A
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5 Series Circuits 5.1 INTRODUCTION
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S the same through series elements
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S Solution: RT � R1 � R2 � R3
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S type of element. In other words,
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S c. V1 � IR1 � (2 A)(4 �)
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S In the above discussion the curre
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S Voltage Sources and Ground Except
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S EXAMPLE 5.14 Find the voltage Vab
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S EXAMPLE 5.19 Using the voltage di
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S ∆V L 120 V 100 V 0 V L voltage
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S EXAMPLE 5.24 Determine the voltag
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S 5.11 APPLICATIONS Holiday Lights
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S wiring, you will find that since
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S and right-click on the mouse. A l
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S FIG. 5.68 Applying Electronics Wo
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S also be used to remind the progra
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S 3. Find the applied voltage E nec
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S 9. Determine the current I and th
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S 40 V I + R 3 R 2 R 1 V 3 - 30 �
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S *28. For the network of Fig. 5.97
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6 Parallel Circuits 6.1 INTRODUCTIO
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P rent level. In other words, as th
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P EXAMPLE 6.4 a. Find the total res
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P R T R 6 � R′ T � �� �
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P d. RT � 30 � � 30 � � 0
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P 0.25 S � 0.1 S � 0.05 S � 0
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P EXAMPLE 6.13 Determine the curren
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P I2 � I4 � I5 12 A � I4 �
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P For the particular case of two pa
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P and (R 1 � R 2)I 1 � R 2I R 1
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P A short circuit is a very low res
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P must therefore be zero volts, as
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P + E - A + - I s + - ensure a posi
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P 12-gage fuse link Filter capacito
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P car such as the lights, air condi
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P careful, you can work with one li
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P In particular, note that m (or M)
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P This time, rather than using mete
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P PROBLEMS ⏐⏐⏐ 205 *6. Determ
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P 14. Using the information provide
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P *21. Find the unknown quantities
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P SECTION 6.8 Open and Short Circui
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7 Series-Parallel Networks 7.1 SERI
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S S P P For parallel resistors R 1
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S S P P a I A E 16.8 V R 1 9 � R
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S S P P I s R T E 24 V R 6 � R1
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S S P P R 3 R 2 7 � 5 � I 3 R 4
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S S P P E 72 V 72 V I5 ���
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S S P P (6 �)I3 6 I6 ���
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S S P P To demonstrate the validity
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S S P P 7.5 POTENTIOMETER LOADING F
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S S P P The Ammeter The maximum cur
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S S P P ammeter or voltmeter becaus
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S S P P 120 V + - VR1 R1 + - 1 �
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S S P P would be created between th
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S S P P Note also that the current
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S S P P 7.9 COMPUTER ANALYSIS PSpic
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Heading Preprocessor directive Defi
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S S P P 3. For the network of Fig.
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S S P P 10. For the network of Fig.
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S S P P 17. For the configuration o
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S S P P 26. For the ladder network
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S S P P 34. Using a 50-mA, 1000-�
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8 Methods of Analysis and Selected
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N A current-source networks, it wil
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N A excellent approximation to drop
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N A EXAMPLE 8.7 Reduce the network
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N A of series elements. Figure 8.20
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N A appearing in Solution 1 in a ve
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N A R 1 E 1 - + + - 4 � 15 V Appl
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N A EXAMPLE 8.11 Consider the same
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N A EXAMPLE 8.13 Find the branch cu
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N A Node a is then used to relate t
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N A 1. Assign a loop current to eac
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N A EXAMPLE 8.18 Find the current t
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N A The nodal analysis method is ap
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N A or I � � � and V2� �
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N A Step 3: Included in Fig. 8.49 f
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N A I 3 V 1 I 1 R 3 10 � 6 A R1 4
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N A EXAMPLE 8.23 Write the nodal eq
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N A EXAMPLE 8.25 Using nodal analys
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N A Solution: The nodal voltages ar
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N A with the bottom of the determin
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N A any unknown quantities if mesh
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N A To obtain the relationships nec
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N A Solution: RB RC (20 �)(10 �
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N A 8.13 APPLICATIONS The Applicati
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N A or outside forces such as light
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N A Schematic with Nodal Voltages W
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N A A photograph of the outside and
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N A PROBLEMS SECTION 8.2 Current So
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N A SECTION 8.4 Current Sources in
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N A *16. For the transistor configu
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N A SECTION 8.8 Mesh Analysis (Form
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N A *37. Using the supernode approa
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N A *49. Repeat Problem 48 for the
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9 Network Theorems 9.1 INTRODUCTION
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Th This final relationship between
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Th The total current through the 4-
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I Th R 1 6 mA R 3 Current divider r
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Th E 1 12 V 6 � 4 V E 2 4 � (a)
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Th R 1 3 � R 2 6 � a R Th b b (
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Th R 1 R 1 6 � 6 � R 4 a 3 �
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Th 6 � R 1 R 2 12 � b R3 a R4 3
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Th Direct Measurement of E Th and R
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Th Conclusion: 5. Draw the Norton e
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Th NORTON’S THEOREM ⏐⏐⏐ 341
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Th E Th I N R N FIG. 9.78 Defining
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Th Note, in particular, that P L is
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Th When R L � R Th, R L h% ��
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Th EXAMPLE 9.14 A dc generator, bat
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Th Note Fig. 9.91, where V1 � V3
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Th that of E 1 and E 3. The total c
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Th combination of elements that wil
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Th RT � R1 � R2 � (R3 � R4)
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Th are presented with a bundle of r
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Th FIG. 9.116 Using PSpice to deter
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Th FIG. 9.119 Using PSpice to deter
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Th FIG. 9.121 Plot resulting from t
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Th 2. Using superposition, find the
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Th *8.Find the Thévenin equivalent
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Th 21. For each network of Fig. 9.1
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Th SECTION 9.8 Reciprocity Theorem
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10 Capacitors 10.1 INTRODUCTION Thu
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The attraction and repulsion betwee
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w � Q, so the dielectric is also
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d � o d d C = 5 µF A (a) C = 0.1
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EXAMPLE 10.4 Find the maximum volta
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Dipped phenolic coating Ceramic die
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lower potential. This capacitor can
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Type: Miniature Axial Electrolytic
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The factor e �t/RC is an exponent
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after five time constants of the ch
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which employs the function e �x a
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Solutions: a. Charging phase: vC
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t2 � (R2 � R3)C � (1 k��3
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a. Find the mathematical expression
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and C t ��t loge�1 � �v
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10.11 THÉVENIN EQUIVALENT: t � R
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Solution: The network is redrawn in
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�v 4 v 3 v2 0 v C (V) 1 t2 t3 �
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and substituting for C T: 1/C 1 V 1
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Solution: As previously discussed,
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Flash Lamp The basic circuitry for
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light in parallel with the capacito
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Black (feed) Ground Black White Gro
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sufficiently large to be considered
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FIG. 10.77 Using PSpice to investig
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Settings-AverageIC dialog box. Anal
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16. Find the distance in millimeter
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29. For the situation of Problem 25
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*40. The capacitor of Fig. 10.100 i
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*47. For the network of Fig. 10.107
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11 Magnetic Circuits 11.1 INTRODUCT
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Magnetic flux lines I Conductor FIG
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EXAMPLE 11.1 For the core of Fig. 1
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Substituting, we have (11.4) The ma
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- H s - B max e Saturation B R d -
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1.4 1.3 1.2 1.1 1.0 0.9 0.8 0.7 0.6
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above is evidenced by the fact that
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An approach frequently employed in
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and the magnetizing force is H (she
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The flux density of the air gap in
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� � 0 Hbelbe � Hbcdelbcde �
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EXAMPLE 11.9 Find the magnetic flux
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Speakers and Microphones Electromag
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4,000,000,000,000 bits of informati
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ingly enough one that perhaps will
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Hall Effect Sensor The Hall effect
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ciently close to establish contact
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SECTION 11.8 Hysteresis 9. For the
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*18. For the series-parallel magnet
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12 Inductors 12.1 INTRODUCTION We h
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Inductors are coils of various dime
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(a) (d) (b) FIG. 12.10 Various type
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ciated with the applied ac signal m
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the voltage across the coil is not
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y 1.0 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0
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12.8 INITIAL VALUES This section wi
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Let us now test the validity of the
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The mathematical expression for the
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v R1 R1 Defined polarity + vL - v L
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iL � (1 � e �t/t ) t � �
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12.12 INDUCTORS IN SERIES AND PARAL
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Applying the current divider rule,
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EXAMPLE 12.12 Find the energy store
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+ Feed 120 V ac - Return ���
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would need for 15 W, not to mention
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will scatter to all sides of the mo
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ing trace appears in the bottom of
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FIG. 12.61 Using PSpice to determin
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Parameters, use 0 s as the Start ti
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*11. Find the waveform for the curr
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*19. For the network of Fig. 12.76:
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*29. The switch of Fig. 12.83 has b
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37. Find the voltage V 1 and the cu
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624 ⏐⏐⏐ THE BASIC ELEMENTS AN
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626 ⏐⏐⏐ THE BASIC ELEMENTS AN
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628 ⏐⏐⏐ THE BASIC ELEMENTS AN
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630 ⏐⏐⏐ SERIES AND PARALLEL a
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632 ⏐⏐⏐ SERIES AND PARALLEL a
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704 ⏐⏐⏐ SERIES AND PARALLEL a
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706 ⏐⏐⏐ SERIES AND PARALLEL a
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16 Series-Parallel ac Networks 16.1
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The total impedance is defined by Z
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to determine V ab. Figure 16.8 clea
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and VL � ILZR � (3.023 mA �0.
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with the result: Converting to pola
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(4,0)�((9,�7)�(8,6)) �1 * (
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E = 120 V ∠ 0° 16.4 APPLICATIONS
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��� ���� ����
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solid inner conductor surrounded by
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The most common coax cables have ch
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amplifier knows how to compensate f
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selecting Value and then Display fo
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also be simply typed in from the ke
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FIG. 16.36 Using the oscilloscope o
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Simulate-Analyses-AC Analysis to ob
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4. For the network of Fig. 16.42: a
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*11. Find the current I for the net
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17 Methods of Analysis and Selected
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N A + V - I - k1V + k 2 V k 3 I + 1
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N A EXAMPLE 17.3 Convert the voltag
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N A Step 3: �E 1 � I 1Z 1 � Z
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N A Format Approach The format appr
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N A work. Note that in this example
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N A analysis in Chapter 8 is sugges
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N A FIG. 17.26 Using Mathcad to ver
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N A EXAMPLE 17.14 Write the nodal e
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N A Solution 1: tions, we have Choo
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N A Solution: The circuit is redraw
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N A EXAMPLE 17.19 Apply nodal analy
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N A For I Z5 � 0, the following m
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N A Substitute into Eq. (17.6) in t
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N A 17.7 �-Y, Y-� CONVERSIONS T
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N A two similar branches. In this e
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N A 1 � 2 � 2 d 1 � 2 � Eac
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N A Now the New Simulation Profile
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N A will appear all over the IPRINT
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N A 4. Convert the voltage source o
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N A *10. Using mesh analysis, deter
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N A *21. Write the nodal equations
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N A 29. Determine whether the Maxwe
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N A GLOSSARY Bridge network A netwo
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792 ⏐⏐⏐ NETWORK THEOREMS (ac)
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794 ⏐⏐⏐ NETWORK THEOREMS (ac)
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796 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 799 and 800:
798 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 801 and 802:
800 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 803 and 804:
802 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 805 and 806:
804 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 807 and 808:
806 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 809 and 810:
808 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 811 and 812:
810 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 813 and 814:
812 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 815 and 816:
814 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 817 and 818:
816 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 819 and 820:
818 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 821 and 822:
820 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 823 and 824:
822 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 825 and 826:
824 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 827 and 828:
826 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 829 and 830:
828 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 831 and 832:
830 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 833 and 834:
832 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 835 and 836:
834 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 837 and 838:
836 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 839 and 840:
838 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 841 and 842:
840 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 843 and 844:
842 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 845 and 846:
844 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 847 and 848:
846 ⏐⏐⏐ NETWORK THEOREMS (ac)
- Page 849 and 850:
848 ⏐⏐⏐ NETWORK THEOREMS (ac)
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850 ⏐⏐⏐ POWER (ac) i p R + v
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852 ⏐⏐⏐ POWER (ac) fulness in
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854 ⏐⏐⏐ POWER (ac) or pL �
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856 ⏐⏐⏐ POWER (ac) i + v - p
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858 ⏐⏐⏐ POWER (ac) v S P Q L
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860 ⏐⏐⏐ POWER (ac) 19.7 THE T
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862 ⏐⏐⏐ POWER (ac) P T = 600
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864 ⏐⏐⏐ POWER (ac) Z T v v�
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866 ⏐⏐⏐ POWER (ac) S = 6757.2
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868 ⏐⏐⏐ POWER (ac) v = 18.19
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870 ⏐⏐⏐ POWER (ac) I + E - Φ
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872 ⏐⏐⏐ POWER (ac) FIG. 19.35
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874 ⏐⏐⏐ POWER (ac) power fact
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876 ⏐⏐⏐ POWER (ac) P q s be s
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878 ⏐⏐⏐ POWER (ac) FIG. 19.39
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880 ⏐⏐⏐ POWER (ac) + E = 100
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882 ⏐⏐⏐ POWER (ac) + E = 30 V
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884 ⏐⏐⏐ POWER (ac) + g P q s
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20 Resonance 20.1 INTRODUCTION This
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ƒ r The total impedance of this ne
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ƒ r reactive power, the larger the
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ƒ r straight line intersecting the
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ƒ r The above condition is derived
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ƒ r 20.6 V R,V L, AND V C (20.23)
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ƒ r E = 10 V ∠0° + - I + - V R
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ƒ r X L 2pfsL 2p(15,915.49 Hz)(60
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ƒ r 1 1 1 and YT � �� � j
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ƒ r Since the voltage across paral
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ƒ r Z p 0 L/C fixed R l3 > R l2 >
- Page 910 and 911:
The fact that the negative term und
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ƒ r The magnitude of the current I
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ƒ r d. Find the voltage VC at reso
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ƒ r c. Rs � ∞ �; therefore,
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ƒ r On the other hand, 1 R l BW
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ƒ r 20.13 APPLICATIONS Stray Reson
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ƒ r fier selection and placement.
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ƒ r FIG. 20.42 Series resonant cir
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ƒ r FIG. 20.44 Parallel resonant n
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ƒ r 27.051 kHz. Clearly, therefore
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ƒ r PROBLEMS PROBLEMS ⏐⏐⏐ 92
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ƒ r 14. For the parallel resonant
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ƒ r *22. For the network of Fig. 2
- Page 936 and 937:
21 Transformers 21.1 INTRODUCTION C
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it will never approach a level of 1
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operation of a transformer. Most tr
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EXAMPLE 21.2 For the iron-core tran
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EXAMPLE 21.3 For the iron-core tran
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+ V g - R s 512 � 120 V Solutions
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e. All the speakers are in parallel
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+ E p - R p L p Cp RC Lm Np Ns Cs E
- Page 952 and 953:
Ip = 10 A ∠ 0° 1 � 2 � Solut
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21.8 SERIES CONNECTION OF MUTUALLY
- Page 956 and 957:
EXAMPLE 21.8 Find the total inducta
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Vg � Ip(Rp � j XLp ) �� �
- Page 960 and 961:
0 B = � m A core �B = �� m
- Page 962 and 963:
employed as an autotransformer. The
- Page 964 and 965:
where M of Zm � qM �90° is pos
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exist only in the line connecting t
- Page 968 and 969:
On/Off switch + 120 V - 60 Hz I fil
- Page 970 and 971:
FIG. 21.51 Using PSpice to determin
- Page 972 and 973:
PROBLEMS SECTION 21.2 Mutual Induct
- Page 974 and 975:
15. For the transformer of Fig. 21.
- Page 976:
21.5. That is, given the speaker im
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978 ⏐⏐⏐ POLYPHASE SYSTEMS per
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980 ⏐⏐⏐ POLYPHASE SYSTEMS 22.
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982 ⏐⏐⏐ POLYPHASE SYSTEMS C B
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984 ⏐⏐⏐ POLYPHASE SYSTEMS the
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986 ⏐⏐⏐ POLYPHASE SYSTEMS C I
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988 ⏐⏐⏐ POLYPHASE SYSTEMS �
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990 ⏐⏐⏐ POLYPHASE SYSTEMS A 3
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992 ⏐⏐⏐ POLYPHASE SYSTEMS Ave
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994 ⏐⏐⏐ POLYPHASE SYSTEMS c.
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996 ⏐⏐⏐ POLYPHASE SYSTEMS A N
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998 ⏐⏐⏐ POLYPHASE SYSTEMS P 1
- Page 1001 and 1002:
1000 ⏐⏐⏐ POLYPHASE SYSTEMS 4.
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1002 ⏐⏐⏐ POLYPHASE SYSTEMS Se
- Page 1005 and 1006:
1004 ⏐⏐⏐ POLYPHASE SYSTEMS Us
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1006 ⏐⏐⏐ POLYPHASE SYSTEMS 12
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1008 ⏐⏐⏐ POLYPHASE SYSTEMS A
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1010 ⏐⏐⏐ POLYPHASE SYSTEMS A
- Page 1013 and 1014:
1012 ⏐⏐⏐ POLYPHASE SYSTEMS 28
- Page 1015 and 1016:
1014 ⏐⏐⏐ POLYPHASE SYSTEMS E
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23 Decibels, Filters, and Bode Plot
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dB Linear scale 6 5 4 3 2 1 log 10
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dB (23.6) 5. The log of a number ta
- Page 1024 and 1025:
dB P dBm � 10 log10 � 1mW �
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dB Output Power. dBs Average value
- Page 1028 and 1029:
dB frequencies is called a filter.
- Page 1030 and 1031:
dB V o = 0.707V i 0 V o Pass-band f
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dB 0° -45° -90° 90° 45° 0° v
- Page 1034 and 1035:
dB 0.707 0.5 23.6 R-C HIGH-PASS FIL
- Page 1036 and 1037:
dB 90° 45° 0° v (V o leads V i )
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dB V max 0.707V max V o BW 0 f1 fc
- Page 1040 and 1041:
dB V i V i 1 and fs � �� (23.
- Page 1042 and 1043:
dB 0.943 0.667 0 c. Dividing all le
- Page 1044 and 1045:
dB Vomin � � RlVi � Rl � R
- Page 1046 and 1047:
dB High-Pass R-C Filter Let us star
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dB Note from the above equations th
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dB for a difference of 90° � 84.
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dB In terms of magnitude and phase,
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dB At f � 0 Hz, the capacitor wil
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dB 0 A v � dB = A v A vmax dB R2
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dB A v dB In region 2 one asymptote
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dB The full idealized Bode response
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dB 90° 45° 0° -45° -90° v (A v
- Page 1064 and 1065:
dB 0 20 log10√1 + f 1 f 2 -6 dB/o
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dB 90° 45° 0° -45° -90° v (A v
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dB In all the situations described
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dB EXAMPLE 23.12 A transistor ampli
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dB which is relatively close to the
- Page 1074 and 1075:
dB Function dB Plot Phase Plot A v
- Page 1076 and 1077:
dB XLmid � 2pfLmid � 2p(1 kHz)(
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dB Calculating the drop in dB will
- Page 1080 and 1081:
dB Alternators in a car are notorio
- Page 1082 and 1083:
dB FIG. 23.93 High-pass R-C filter
- Page 1084 and 1085:
dB were set in the Property Editor
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dB PROBLEMS SECTION 23.1 Logarithms
- Page 1088 and 1089:
dB PROBLEMS ⏐⏐⏐ 1087 SECTION
- Page 1090 and 1091:
dB d. Sketch the actual response, i
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dB PROBLEMS ⏐⏐⏐ 1091 SECTION
- Page 1094 and 1095:
24 Pulse Waveforms and the R-C Resp
- Page 1096 and 1097:
Pulse Width The pulse width (tp), o
- Page 1098 and 1099:
8 7 0 - 4 v (V) 1 2 3 4 5 6 7 8 9 1
- Page 1100 and 1101:
EXAMPLE 24.3 Determine the pulse re
- Page 1102 and 1103:
8 7 6 5 4 3 2 1 By Eq. (24.5), Vb
- Page 1104 and 1105:
. When the switch is first closed,
- Page 1106 and 1107:
R-C circuit as shown in Fig. 24.26,
- Page 1108 and 1109:
Note in Figs. 24.29 and 24.30 that
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For the next interval, Vi � 2.33
- Page 1112 and 1113:
Although both examples provided abo
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opener or the car alarm transmitter
- Page 1116 and 1117:
only one TV. Then there are smart r
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FIG. 24.49 Plot of v pulse, v C, an
- Page 1120 and 1121:
SECTION 24.3 Pulse Repetition Rate
- Page 1122:
Programming Language (C��, QBAS
- Page 1125 and 1126:
1124 ⏐⏐⏐ NONSINUSOIDAL CIRCUI
- Page 1127 and 1128:
1126 ⏐⏐⏐ NONSINUSOIDAL CIRCUI
- Page 1129 and 1130:
1128 ⏐⏐⏐ NONSINUSOIDAL CIRCUI
- Page 1131 and 1132:
1130 ⏐⏐⏐ NONSINUSOIDAL CIRCUI
- Page 1133 and 1134:
1132 ⏐⏐⏐ NONSINUSOIDAL CIRCUI
- Page 1135 and 1136:
1134 ⏐⏐⏐ NONSINUSOIDAL CIRCUI
- Page 1137 and 1138:
1136 ⏐⏐⏐ NONSINUSOIDAL CIRCUI
- Page 1139 and 1140:
1138 ⏐⏐⏐ NONSINUSOIDAL CIRCUI
- Page 1141 and 1142:
1140 ⏐⏐⏐ NONSINUSOIDAL CIRCUI
- Page 1143 and 1144:
1142 ⏐⏐⏐ NONSINUSOIDAL CIRCUI
- Page 1145 and 1146:
1144 ⏐⏐⏐ NONSINUSOIDAL CIRCUI
- Page 1147 and 1148:
1146 ⏐⏐⏐ NONSINUSOIDAL CIRCUI
- Page 1150 and 1151:
26 System Analysis: An Introduction
- Page 1152 and 1153:
Zi � � Ei � (ohms, �) (26.1
- Page 1154 and 1155:
Z i, from which the resistive and r
- Page 1156 and 1157:
26.3 THE VOLTAGE GAINS A vNL ,A v,
- Page 1158 and 1159:
E o � and Av � � (26.8) Eo RL
- Page 1160 and 1161:
Zi and Ai ��Av�� (26.10) R
- Page 1162 and 1163:
EXAMPLE 26.5 Given the system of Fi
- Page 1164 and 1165:
the voltage gain substituted is als
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h. A vT � A v1 ⋅ A v2 ⋅ A v3
- Page 1168 and 1169:
E 1 + - I 1 1 1′ Z 1 Z 3 FIG. 26.
- Page 1170 and 1171:
parameters have been determined. As
- Page 1172 and 1173:
y 22 I2 2 y22 � �� E The dete
- Page 1174 and 1175:
Y T � Y 2 � Y 3 and I 2 � E 2
- Page 1176 and 1177:
h 12 h12 � � E1 � E 2 I 1 �
- Page 1178 and 1179:
Solutions: a. Using the current div
- Page 1180 and 1181:
and I 2 � � � �h o� E 2 T
- Page 1182 and 1183:
h 22 and �E1 � I1 � �I2 Dh
- Page 1184 and 1185:
The Simulation Settings were AC Swe
- Page 1186 and 1187:
2. For a system with Ei � 120 V
- Page 1188 and 1189:
10. For the system of Fig. 26.65(a)
- Page 1190 and 1191:
18. a. Determine the impedance (z)
- Page 1192 and 1193:
GLOSSARY Admittance (y) parameters
- Page 1194 and 1195:
Appendix A PSpice, Electronics Work
- Page 1196 and 1197:
Appendix B CONVERSION FACTORS To Co
- Page 1198 and 1199:
To Convert from To Multiply by Maxw
- Page 1200 and 1201:
Col. Col. 1 2 ------- �a1 b1� D
- Page 1202 and 1203:
The use of determinants is not limi
- Page 1204 and 1205:
1 0 1 a1 a2 a3 b1 b2 b3 0 3 2 c1 c2
- Page 1206 and 1207:
� 1[6 � 1] � 3[�(6 � 3)]
- Page 1208 and 1209:
Appendix E THE GREEK ALPHABET Lette
- Page 1210 and 1211:
Appendix G MAXIMUM POWER TRANSFER C
- Page 1212 and 1213:
Appendix H ANSWERS TO SELECTED ODD-
- Page 1214 and 1215:
Chapter 8 1. 28 V 3. (a) I1 � 12
- Page 1216 and 1217:
(b) 2.5 kHz (c) �25 mV 39. (a) 1.
- Page 1218 and 1219:
9. (a) R: 38.99 W, L:0W,C:0W (b) R:
- Page 1220:
1 ��f 10 c: �0.043 dB, 10fc: