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146 ⏐⏐⏐ SERIES CIRCUITS S<br />

E<br />

(a)<br />

–<br />

E<br />

+<br />

E<br />

+<br />

–<br />

R L<br />

–<br />

E<br />

+<br />

– E +<br />

POWER SUPPLY<br />

(a) (b)<br />

FIG. 5.51<br />

(a) Sources of dc voltage; (b) equivalent circuit.<br />

R int<br />

I L = 0<br />

E<br />

(b)<br />

+<br />

V NL = E<br />

sider the effects of the internal resistance, the output voltage will be E<br />

volts only when no-load (IL � 0) conditions exist. When a load is connected<br />

[Fig. 5.52(c)], the output voltage of the voltage source will<br />

decrease due to the voltage drop across the internal resistance.<br />

By applying Kirchhoff’s voltage law around the indicated loop of<br />

Fig. 5.52(c), we obtain<br />

E � ILRint � VL � 0<br />

or, since E � VNL we have V NL � I LR int � V L � 0<br />

and VL � VNL � ILRint (5.13)<br />

If the value of Rint is not available, it can be found by first solving for<br />

Rint in the equation just derived for VL; that is,<br />

Rint �� VNL � VL � � �<br />

I<br />

VNL<br />

� � �<br />

I<br />

ILRL �<br />

I<br />

L<br />

and Rint � � (5.14)<br />

VNL<br />

� � RL I<br />

A plot of the output voltage versus current appears in Fig. 5.53 for<br />

the dc generator having the circuit representation of Fig. 5.51(b). Note<br />

that any increase in load demand, starting at any level, causes an additional<br />

drop in terminal voltage due to the increasing loss in potential<br />

across the internal resistance. At maximum current, denoted by I FL, the<br />

L<br />

+<br />

–<br />

L<br />

Rint + –<br />

FIG. 5.52<br />

Voltage source: (a) ideal, R int � 0 �; (b) determining V NL; (c) determining R int .<br />

–<br />

IL E<br />

(c)<br />

L<br />

R int<br />

E<br />

V L<br />

+<br />

–<br />

I L<br />

+<br />

–<br />

R L

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