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1100 ⏐⏐⏐ PULSE WAVEFORMS AND THE R-C RESPONSE<br />

EXAMPLE 24.5 Determine the pulse repetition rate and duty cycle<br />

for the trigger waveform of Fig. 24.14.<br />

Solution:<br />

div.<br />

T � (2.6 div.)(10 ms/div.) � 26 ms<br />

1 1<br />

prf � � ���38,462 kHz<br />

T 26 ms<br />

tp � (0.2 div.)(10 ms/div.) � 2 ms<br />

2 ms<br />

Duty cycle � � �100% ���100% � 7.69%<br />

T<br />

26 ms<br />

24.4 AVERAGE VALUE<br />

t p<br />

v<br />

V<br />

0.5 V<br />

t<br />

0 Horizontal sensitivity = 10 �s/div. �<br />

FIG. 24.14<br />

Example 24.5.<br />

The average value of a pulse waveform can be determined using one of<br />

two methods. The first is the procedure outlined in Section 13.6, which<br />

can be applied to any alternating waveform. The second can be applied<br />

only to pulse waveforms since it utilizes terms specifically related to<br />

pulse waveforms; that is,<br />

V av � (duty cycle)(peak value) � (1 � duty cycle)(V b)<br />

(24.5)<br />

In Eq. (24.5), the peak value is the maximum deviation from the reference<br />

or zero-volt level, and the duty cycle is in decimal form. Equation<br />

(24.5) does not include the effect of any tilt pulse waveforms with<br />

sloping sides.<br />

EXAMPLE 24.6 Determine the average value for the periodic pulse<br />

waveform of Fig. 24.15.<br />

Solution: By the method of Section 13.6,<br />

G �<br />

T � (12 � 2) ms � 10 ms<br />

G � �<br />

44 � 10<br />

� �4.4 mV<br />

�9<br />

32 � 10<br />

���6<br />

10 � 10 �9 � 12 � 10 �9<br />

���<br />

10 � 10 �6<br />

area under curve<br />

��<br />

T<br />

(8 mV)(4 ms) � (2 mV)(6 ms)<br />

����<br />

10 ms

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