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the equivalent dc value. In the analysis of electronic circuits to be considered<br />

in a later course, both dc and ac sources of voltage will be<br />

applied to the same network. It will then be necessary to know or determine<br />

the dc (or average value) and ac components of the voltage or current<br />

in various parts of the system.<br />

EXAMPLE 13.13 Determine the average value of the waveforms of<br />

Fig. 13.37.<br />

0<br />

v 1<br />

10 V<br />

(Square wave)<br />

1 2 3 4 t (ms)<br />

–10 V<br />

(a)<br />

0<br />

FIG. 13.37<br />

Example 13.13.<br />

v 2<br />

14 V<br />

1 2 3 4 t (ms)<br />

–6 V<br />

Solutions:<br />

a. By inspection, the area above the axis equals the area below over<br />

one cycle, resulting in an average value of zero volts. Using Eq.<br />

(13.26):<br />

(10 V)(1 ms) � (10 V)(1 ms)<br />

G �����<br />

2 ms<br />

0<br />

���0 V<br />

2 ms<br />

b. Using Eq. (13.26):<br />

(14 V)(1 ms) � (6 V)(1 ms)<br />

G ����<br />

2 ms<br />

14 V � 6 V 8 V<br />

��� ���4 V<br />

2 2<br />

as shown in Fig. 13.38.<br />

In reality, the waveform of Fig. 13.37(b) is simply the square wave<br />

of Fig. 13.37(a) with a dc shift of 4 V; that is,<br />

v2 � v1 � 4 V<br />

EXAMPLE 13.14 Find the average values of the following waveforms<br />

over one full cycle:<br />

a. Fig. 13.39.<br />

b. Fig. 13.40.<br />

(b)<br />

14 V<br />

AVERAGE VALUE ⏐⏐⏐ 541<br />

4 V<br />

0 1<br />

–6 V<br />

2 3 4 t (ms)<br />

FIG. 13.38<br />

Defining the average value for the waveform<br />

of Fig. 13.37(b).<br />

3<br />

0<br />

–1<br />

v (V)<br />

1 cycle<br />

4 8<br />

FIG. 13.39<br />

Example 13.14, part (a).<br />

t (ms)

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