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228 ⏐⏐⏐ SERIES-PARALLEL NETWORKS<br />

S<br />

S P P<br />

As noted above in the highlighted statement, the more the current<br />

drain, the greater the change in terminal voltage with the application of<br />

the load. This is certainly verified by the fact that I L 2 is about 33.5 times<br />

larger with the 20-� loads.<br />

The next example is a design exercise. The voltage and current ratings<br />

of each load are provided, along with the terminal ratings of the<br />

supply. The required voltage divider resistors must be found.<br />

EXAMPLE 7.11 Determine R 1, R 2, and R 3 for the voltage divider supply<br />

of Fig. 7.36. Can 2-W resistors be used in the design?<br />

I s = 50 mA<br />

E 72 V<br />

R 1<br />

R 2<br />

R 3<br />

a<br />

b<br />

R L2<br />

10 mA<br />

+<br />

–12 V<br />

20 V<br />

–<br />

R L1<br />

20 mA<br />

+<br />

60 V<br />

FIG. 7.36<br />

Example 7.11.<br />

Solution: R3: R3 � � VR<br />

3<br />

� � �<br />

IR3 VR<br />

12<br />

V<br />

3<br />

� � �� � 240 �<br />

Is<br />

50<br />

mA<br />

PR3 � (IR3 ) 2 R3 � (50 mA) 2 240 ��0.6 W < 2 W<br />

R1: Applying Kirchhoff’s current law to node a:<br />

Is � IR1 � IL1 � 0<br />

and IR1 � Is � IL1 � 50 mA � 20 mA<br />

� 30 mA<br />

R1 � � VR<br />

1<br />

� ��<br />

IR1 VL � V<br />

1<br />

L2 60 V � 20 V<br />

� ��� �<br />

IR<br />

30 mA<br />

1<br />

� 1.33 k�<br />

PR1 � (IR1 ) 2 R1 � (30 mA) 2 1.33 k��1.197 W < 2 W<br />

R2: Applying Kirchhoff’s current law at node b:<br />

IR1 � IR2 � IL2 � 0<br />

and IR2 � IR1 � IL2 � 30 mA � 10 mA<br />

� 20 mA<br />

R2 � � �1 k�<br />

PR2 � (IR2 ) 2 R2 � (20 mA) 2 40 V<br />

�<br />

30 mA<br />

VR2 20 V<br />

� �<br />

IR2 20 mA<br />

1 k��0.4 W < 2 W<br />

Since PR1 , PR2 , and PR3 are less than 2 W, 2-W resistors can be used for<br />

the design.<br />

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