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698 ⏐⏐⏐ SERIES AND PARALLEL ac CIRCUITS<br />

+<br />

e = 6 sin(314t + 60°)<br />

–<br />

E = 10 V(rms)<br />

f = 1 kHz<br />

+<br />

–<br />

E = 12 V(rms)<br />

f = 40 kHz<br />

R<br />

+<br />

–<br />

+<br />

E = 120 V ∠ 20°<br />

–<br />

Z T<br />

R = 3 k�<br />

+ v – R<br />

FIG. 15.123<br />

Problem 11.<br />

29.94 mA(rms)<br />

I<br />

L<br />

FIG. 15.125<br />

Problem 13.<br />

X L = 2 k�<br />

+ v – L<br />

Scope = 8.27 V( p-p)<br />

+<br />

R<br />

–<br />

10 k�<br />

FIG. 15.126<br />

Problem 14.<br />

2 k�<br />

+ V –<br />

1<br />

(a)<br />

X C = 1 k�<br />

+<br />

v<br />

–<br />

C<br />

+<br />

Scope = 21.28 V( p-p)<br />

–<br />

C<br />

6 k�<br />

+ V –<br />

2<br />

i<br />

a c<br />

11. Repeat Problem 10 for the circuit of Fig. 15.123.<br />

12. Using the oscilloscope reading of Fig. 15.124, determine<br />

the resistance R.<br />

+ R<br />

+<br />

E = 20 V(rms) 80 � Scope = 45.27 V( p-p)<br />

–<br />

–<br />

FIG. 15.124<br />

Problem 12.<br />

*13. Using the DMM current reading and the oscilloscope<br />

measurement of Fig. 15.125:<br />

a. Determine the inductance L.<br />

b. Find the resistance R.<br />

*14. Using the oscilloscope reading of Fig. 15.126, determine<br />

the capacitance C.<br />

+<br />

E = 60 V ∠ 5°<br />

–<br />

FIG. 15.127<br />

Problem 15.<br />

SECTION 15.4 Voltage Divider Rule<br />

15. Calculate the voltages V1 and V2 for the circuit of Fig.<br />

15.127 in phasor form using the voltage divider rule.<br />

6.8 �<br />

(b)<br />

40 �<br />

+ V –<br />

1<br />

9 �<br />

+ –<br />

V2

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