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1156 ⏐⏐⏐ SYSTEM ANALYSIS: AN INTRODUCTION<br />

+<br />

–<br />

A vNL E i<br />

R o<br />

+<br />

E o<br />

–<br />

R L<br />

FIG. 26.14<br />

Applying a load to the output of Fig. 26.13.<br />

If we expand Eq. (26.5) as follows:<br />

Eo �<br />

Eg<br />

Eo �<br />

Eg<br />

A vT � � (1) � � � � ⋅<br />

Ei �<br />

Eg<br />

then A vT � A v (if loaded)<br />

Ei or AvT � AvNL � (if unloaded)<br />

Eg<br />

The relationship between Ei and Eg can be determined from Fig.<br />

26.12 if we recognize that Ei is across the input impedance Zi and thus<br />

apply the voltage divider rule as follows:<br />

Zi(Eg) Ei ��<br />

Zi � Rg Ei Zi or � ��<br />

Eg Zi � Rg Substituting into the above relationships will result in<br />

Zi AvT � Av�� Zi � Rg Zi AvT � AvNL�� Zi � Rg Eo Ei � �<br />

Eg Ei<br />

Eo �<br />

Ei<br />

E i<br />

� Eg<br />

(if loaded) (26.6)<br />

(if unloaded) (26.7)<br />

A two-port equivalent model for an unloaded system based on the<br />

definitions of Z i, Z o, and A vNL is provided in Fig. 26.13. Both Z i and Z o<br />

appear as resistive values since this is typically the case for most electronic<br />

amplifiers. However, both Z i and Z o can have reactive components<br />

and not invalidate the equivalency of the model.<br />

+<br />

E i<br />

–<br />

I i<br />

Z i<br />

R i<br />

+<br />

AvNLEi –<br />

Z o<br />

R o<br />

FIG. 26.13<br />

Equivalent model for two-port amplifier.<br />

The input impedance is defined by Z i � E i/I i and the voltage E o �<br />

A vNL E i in the absence of a load, resulting in A vNL � E o/E i as defined.<br />

The output impedance is defined with E i set to zero volts, resulting in<br />

A vNL E i � 0 V, which permits the use of a short-circuit equivalent for the<br />

controlled source. The result is Z o � E o/I o, as defined, and the parameters<br />

and structure of the equivalent model are validated.<br />

If a load is applied as in Fig. 26.14, an application of the voltage<br />

divider rule will result in<br />

I 2<br />

+<br />

E o<br />

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