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Col. Col.<br />

1 2<br />

–––––––<br />

�a1 b1� Determinant � D �<br />

�a<br />

� a1b2 � a2b1 2 b2� (C.3)<br />

The expanded value is obtained by first multiplying the top left element<br />

by the bottom right and then subtracting the product of the lower<br />

left and upper right elements. This particular determinant is referred to<br />

as a second-order determinant, since it contains two rows and two<br />

columns.<br />

It is important to remember when using determinants that the<br />

columns of the equations, as indicated in Eqs. (C.1a) and (C.1b), must<br />

be placed in the same order within the determinant configuration. That<br />

is, since a 1 and a 2 are in column 1 of Eqs. (C.1a) and (C.1b), they must<br />

be in column 1 of the determinant. (The same is true for b 1 and b 2.)<br />

Expanding the entire expression for x and y, we have the following:<br />

EXAMPLE C.1 Evaluate the following determinants:<br />

�2 2�<br />

a. � (2)(4) � (3)(2) � 8 � 6 � 2<br />

�3 4�<br />

�4 �1�<br />

b. � (4)(2) � (6)(�1) � 8 � 6 � 14<br />

�6 �2�<br />

� 0 �2�<br />

c. � (0)(4) � (�2)(�2) � 0 � 4 � �4<br />

��2 �4�<br />

�0 10�<br />

d. � (0)(10) � (3)(0) � 0<br />

�3 10�<br />

�c 1 b 1�<br />

�c 2 b 2 � c 1b 2 � c 2b 1<br />

x � ––––––– � ––––––––––<br />

�a 1 b 1� a 1b 2 � a 2b 1<br />

�a 2 b 2 �<br />

�a 1 c 1�<br />

�a 2 c 2 � a 1c 2 � a 2c 1<br />

y � ––––––– � ––––––––––<br />

�a 1 b 1� a 1b 2 � a 2b 1<br />

�a 2 b 2 �<br />

EXAMPLE C.2 Solve for x and y:<br />

2x � y � 3<br />

3x � 4y � 2<br />

Solution:<br />

�3 1�<br />

�2 4� (3)(4) � (2)(1) 12 � 2 10<br />

x ����� ��� � � 2<br />

�2 1� (2)(4) � (3)(1) 8 �3 5<br />

�3 4�<br />

(C.4a)<br />

(C.4b)<br />

APPENDIX C ⏐⏐⏐ 1199

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