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Composite Materials Research Progress

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152<br />

⎧<br />

UU = ⎨<br />

⎩<br />

⎧<br />

UD = ⎨<br />

⎩<br />

C1<br />

C 2<br />

C3<br />

⎧<br />

= ⎨<br />

⎩<br />

⎧<br />

= ⎨<br />

⎩<br />

*<br />

τ / + 1,<br />

k<br />

i i j<br />

0<br />

*<br />

τ −1/<br />

,<br />

k<br />

i i j<br />

1<br />

2<br />

1<br />

0<br />

0.<br />

75<br />

⎧0<br />

⎪<br />

= ⎨1<br />

⎪<br />

⎩2<br />

Yuanxin Zhou, Hassan Mahfuz, Vijaya Rangari et al.<br />

element (i,j)~(i,j+1) unbroken<br />

element (i,j)~(i,j+1) broken<br />

interface (i,j)~(i+1,j) unbroken<br />

interface (i,j)~(i+1,j) broken<br />

interface (i-1,j)~(i,j) unbroken<br />

interface (i-1,j)~(i,j) broken<br />

element broken<br />

no element broken<br />

element broken<br />

no element broken<br />

both side matrix broken<br />

single side matrix brokes<br />

no matrix broken<br />

C 4<br />

C<br />

5<br />

1 i ≠ 1<br />

= ⎨⎧<br />

⎩0 i = 1<br />

1 i ≠ n<br />

= ⎨⎧<br />

⎩0 i = n<br />

Using the successive over-relaxation, we have<br />

[ ] [ ] ( )[ ] 1<br />

k q k q<br />

k q−<br />

U = U + 1−<br />

λ U<br />

i,<br />

j<br />

λ (15)<br />

i,<br />

j<br />

where, λ is the relaxation factor, which controls the convergence speed of solution, and q is<br />

the times of iteration.<br />

k<br />

k<br />

i,<br />

j<br />

U i,<br />

j is the right side of Equation (14). After U i,<br />

j is obtained, the<br />

stress of the segment of fiber and matrix can be calculated from following expression:

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