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history of mathematics - National STEM Centre

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The full title is Discours<br />

de la methode pour bien<br />

conduire sa raison et<br />

chercher la verite dans<br />

les sciences.<br />

8 An overview <strong>of</strong> La Geometrie<br />

to construct all problems, more and more complex, ad infinitum; for in the<br />

case <strong>of</strong> a mathematical progression, whenever the first two or three terms<br />

are given, it is easy to find the rest.<br />

40 I hope that posterity will judge me kindly, not only as to the things<br />

which I have explained, but also as to those which I have intentionally<br />

omitted so as to leave to others the pleasure <strong>of</strong> discovery.<br />

The method <strong>of</strong> normals<br />

Descartes wrote La Geometrie as an appendix to his philosophical work Discours.<br />

Another appendix is Dioptrique, a treatment on geometrical optics. To draw the<br />

light path made by an incoming ray on a lens, it is essential to construct the normal<br />

to a curve. In La Geometrie Descartes shows a method for constructing normals.<br />

Figure 8.1 shows part <strong>of</strong> an ellipse, as it appeared in La Geometrie.<br />

Here is Descartes's solution to finding the normal to a curve, when the curve is an<br />

ellipse. The method is based on the following idea.<br />

41 ... observe that if the point P fulfils the required conditions, the circle<br />

about P as centre and passing through the point C will touch but not cut<br />

the curve CE; but if this point P be ever so little nearer to or farther from A<br />

than it should be, this circle must cut the curve not only ate but also in<br />

another point.<br />

In short, point P, the centre <strong>of</strong> a circle with radius PC, has a fixed place on GA, as<br />

the circle intersects with the ellipse in C. If PC were not perpendicular to the ellipse,<br />

the circle would intersect with the ellipse at another point as well.<br />

Descartes names various known and unknown quantities.<br />

42 Suppose the problem solved, and let the required line be CP. Produce<br />

CPto meet the straight line GA, to whose points the points <strong>of</strong> CE are to be<br />

related. Then, let MA = CB = >•; and CM = BA = x. An equation must be<br />

found expressing the relation between x and v. I let PC = s, PA = v,<br />

whence PM = v~y.<br />

The ellipse and the circle can be represented as two equations in x and y (the<br />

parameters <strong>of</strong> the ellipse are known, so its equation can be found). The problem can<br />

now be solved algebraically. You can eliminate x or y from the equations, leaving<br />

one equation with one unknown quantity.<br />

Suppose that C is the point <strong>of</strong> contact <strong>of</strong> the ellipse and the circle. What happens<br />

then? Or, put in another way, what happens if the circle and the ellipse have two<br />

coincident points <strong>of</strong> intersection?<br />

I<br />

43 ... and when the points coincide, the roots are exactly equal, that is<br />

to say, the circle through C will touch the curve CE at the point C without<br />

cutting it.<br />

In that case the equation has a double solution.<br />

In Activity 8.9, you will retrace this solution with a concrete example.<br />

107

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