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history of mathematics - National STEM Centre

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: = vtcoscot, y = vt sin cot; r = vO<br />

3 a (vcot 2 cos(cot-^n),vcot 2 sm(cot-^n)} or<br />

vox sin (at, -van cos ox<br />

)<br />

u b r- Gradient A- t T>T PT = —————————— -at cos cot -sin cot ; from the<br />

cot sin cot - cos cot<br />

_ . . . , .. . dy I Ax<br />

Cartesian parametric equation the gradient is -^- / — .<br />

dt I At<br />

which leads to the same result.<br />

. „ ...... , . . , OT rco<br />

4 From the similar right-angled triangles —— = — .<br />

r v<br />

Using r = vt leads to the result. The length <strong>of</strong> the arc PK<br />

is also rcot .<br />

Activity 9.3, page 115<br />

b z-z' = e 2 + e(2b-x)<br />

c If the coefficient, (2b - x), <strong>of</strong> e was negative, then<br />

you could find a small positive value <strong>of</strong> e such that<br />

z < z' , and z is not the maximum. Similarly, when the<br />

coefficient <strong>of</strong> e is positive. Therefore the coefficient <strong>of</strong> e<br />

is zero.<br />

2 a z' = a2 X + e-X + e 3<br />

b<br />

c X 2 = \a 2 , giving the two solutions X = -"^ a - You<br />

need to check which gives the maximum by another<br />

method.<br />

Activity 9.4, page 116<br />

b x + e, a<br />

2 4 - 2s) + se 2 (lx 2 - s 2 ) + X 2e3 }<br />

3 a 5 = \x<br />

c Differentiate to find that — = — ~- , and then use the<br />

ck 3y 2<br />

equation <strong>of</strong> the curve to show that you can write this as — .<br />

s<br />

Activity 9.5, page 116<br />

.<br />

1 a \ x + e,<br />

CO<br />

=a(<br />

14 Answers<br />

c e(3x 2s 2 - 2xs 3 ) + e 2 (lx 2s -s 3 ) + x 2 e 3 = 0<br />

d (3* V - 2xs 3 ) + e(3x 2s - s 3 ) + x 2e 2 = 0<br />

2 ^ = |jc<br />

Activity 9.7, page 118<br />

1 w, omn. w, xw , ult. xxomn. w, omn.omn. w<br />

Activity 9.8, page 119<br />

Activity 10.1, page 124<br />

1 In a practical way negative numbers arose naturally in<br />

accounting and financial systems. This is the way that they<br />

were first used by the Chinese about 2000 years ago. A<br />

positive number might have been used to represent money<br />

received while a negative number represented the opposite,<br />

that is money spent.<br />

2 a A consistent interpretation <strong>of</strong> addition is as a<br />

movement to the right <strong>of</strong> the number line through a certain<br />

distance.<br />

+3<br />

H——\——\——\——\——\——I—<br />

-1012345<br />

2 + 3 = 5<br />

Thus you can justify that the result <strong>of</strong> adding 3 to 2 gives 5.<br />

This model gives you the same result if you started with 3<br />

and added 2 to it. Your model is therefore consistent with<br />

the rules <strong>of</strong> addition as it should be.<br />

177

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