history of mathematics - National STEM Centre
history of mathematics - National STEM Centre
history of mathematics - National STEM Centre
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: = vtcoscot, y = vt sin cot; r = vO<br />
3 a (vcot 2 cos(cot-^n),vcot 2 sm(cot-^n)} or<br />
vox sin (at, -van cos ox<br />
)<br />
u b r- Gradient A- t T>T PT = —————————— -at cos cot -sin cot ; from the<br />
cot sin cot - cos cot<br />
_ . . . , .. . dy I Ax<br />
Cartesian parametric equation the gradient is -^- / — .<br />
dt I At<br />
which leads to the same result.<br />
. „ ...... , . . , OT rco<br />
4 From the similar right-angled triangles —— = — .<br />
r v<br />
Using r = vt leads to the result. The length <strong>of</strong> the arc PK<br />
is also rcot .<br />
Activity 9.3, page 115<br />
b z-z' = e 2 + e(2b-x)<br />
c If the coefficient, (2b - x), <strong>of</strong> e was negative, then<br />
you could find a small positive value <strong>of</strong> e such that<br />
z < z' , and z is not the maximum. Similarly, when the<br />
coefficient <strong>of</strong> e is positive. Therefore the coefficient <strong>of</strong> e<br />
is zero.<br />
2 a z' = a2 X + e-X + e 3<br />
b<br />
c X 2 = \a 2 , giving the two solutions X = -"^ a - You<br />
need to check which gives the maximum by another<br />
method.<br />
Activity 9.4, page 116<br />
b x + e, a<br />
2 4 - 2s) + se 2 (lx 2 - s 2 ) + X 2e3 }<br />
3 a 5 = \x<br />
c Differentiate to find that — = — ~- , and then use the<br />
ck 3y 2<br />
equation <strong>of</strong> the curve to show that you can write this as — .<br />
s<br />
Activity 9.5, page 116<br />
.<br />
1 a \ x + e,<br />
CO<br />
=a(<br />
14 Answers<br />
c e(3x 2s 2 - 2xs 3 ) + e 2 (lx 2s -s 3 ) + x 2 e 3 = 0<br />
d (3* V - 2xs 3 ) + e(3x 2s - s 3 ) + x 2e 2 = 0<br />
2 ^ = |jc<br />
Activity 9.7, page 118<br />
1 w, omn. w, xw , ult. xxomn. w, omn.omn. w<br />
Activity 9.8, page 119<br />
Activity 10.1, page 124<br />
1 In a practical way negative numbers arose naturally in<br />
accounting and financial systems. This is the way that they<br />
were first used by the Chinese about 2000 years ago. A<br />
positive number might have been used to represent money<br />
received while a negative number represented the opposite,<br />
that is money spent.<br />
2 a A consistent interpretation <strong>of</strong> addition is as a<br />
movement to the right <strong>of</strong> the number line through a certain<br />
distance.<br />
+3<br />
H——\——\——\——\——\——I—<br />
-1012345<br />
2 + 3 = 5<br />
Thus you can justify that the result <strong>of</strong> adding 3 to 2 gives 5.<br />
This model gives you the same result if you started with 3<br />
and added 2 to it. Your model is therefore consistent with<br />
the rules <strong>of</strong> addition as it should be.<br />
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