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history of mathematics - National STEM Centre

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14 Answers<br />

<strong>of</strong> multiplication by negative numbers when the<br />

inequality must be reversed. So if a < b and we multiply<br />

both sides <strong>of</strong> the inequality by c < 0, then aobc. You<br />

know that you have to reverse the inequality when you<br />

multiply by a negative number. This means that there is<br />

no contradiction in the rules <strong>of</strong> multiplication when they<br />

are applied to negative numbers as Arnauld suggests.<br />

Activity 10.11, page 131<br />

1 a Lists <strong>of</strong> assumptions<br />

Euler<br />

• assumes that the outcome <strong>of</strong> multiplying together two<br />

numbers is not affected by the order in which we take<br />

the two numbers<br />

• models a negative number as a debt and uses obvious<br />

properties <strong>of</strong> debts to infer properties <strong>of</strong> negative<br />

numbers<br />

• assumes that the product <strong>of</strong> two negative numbers<br />

must be either a positive or a negative number, that is,<br />

it cannot be something new<br />

• assumes that if you take a number and in turn<br />

multiply it by different numbers then the outcome<br />

cannot be the same in both cases<br />

• assumes that when multiplying two numbers together<br />

it is possible to calculate the size (absolute value) <strong>of</strong><br />

the product by multiplying together the sizes<br />

(absolute values) <strong>of</strong> the individual numbers.<br />

Saunderson<br />

• assumes that you can establish that numbers are in<br />

arithmetic progression if there are three or more <strong>of</strong><br />

them to consider<br />

• assumes that if you know the first two terms <strong>of</strong> an<br />

arithmetic progression, then the third can easily be<br />

found<br />

• assumes that if all the terms in an arithmetic<br />

progression are multiplied by the same factor then the<br />

resultant terms (taken in the same order) will also<br />

form an arithmetic progression<br />

• assumes that, even though you might start with an<br />

arithmetic progression with decreasing terms, having<br />

multiplied each by the same factor then the outcome<br />

may be a progression with increasing terms, or vice<br />

versa.<br />

b Arnauld's objections to negative numbers are<br />

summarised below to inform the debate. Arnauld's<br />

objection relates fundamentally to ratios <strong>of</strong> numbers. He<br />

believes that 1 is to a what b is to ab. In other words he<br />

believes that 1 : a is equivalent to b : ab. Examples are:<br />

1 : 3 is equivalent to 4:12;<br />

180<br />

1 : \ is equivalent to -5-: -^.<br />

But he does not believe that 1: - 4 is equivalent to<br />

-5:20.<br />

The reason he gives is that 1 and - 4 cannot be in the<br />

same ratio as -5 and 20 because 1 > -4 whereas<br />

-5 < 20. On that basis alone he disbelieves the rule for<br />

multiplying negative numbers together.<br />

How might a debate between Euler and Arnauld have<br />

been played out on the basis <strong>of</strong> the extracts? It all<br />

depends on the different assumptions that each makes<br />

about operations <strong>of</strong> numbers.<br />

Presumably Arnauld would be prepared to accept that<br />

1: - 3 is equivalent to 4 : - 12 since his ordering<br />

principle applies. In a debate Arnauld could be persuaded<br />

to accept that —b multiplied by a (where a and b are both<br />

positive) produces a negative result. However he would<br />

not accept that 1 : 4 is equivalent to -3: -12 since this<br />

violates the ordering principle, and thus presumably<br />

would not accept that a multiplied by -b is valid.<br />

This logically means that Arnauld cannot accept that a<br />

times —b is the same as —b times a.<br />

On the other hand Euler assumes that the order in which<br />

you multiply a positive by a negative number does not<br />

affect the outcome. A debate between Euler and Arnauld<br />

could centre on this difference <strong>of</strong> opinion with one trying<br />

to convince the other <strong>of</strong> his view. Euler could be made to<br />

justify his assumption. This might be the chink in Euler's<br />

or Arnauld's armour.<br />

Saunderson and Arnauld have more obvious differences<br />

<strong>of</strong> opinion. Saunderson considers numbers in arithmetic<br />

progression; for example, the decreasing sequence 3, 0,<br />

-3. By multiplying each <strong>of</strong> the numbers in the sequence<br />

by - 4 say, he assumes we get another sequence which<br />

starts with -12,0. The third member <strong>of</strong> the sequence<br />

must be 12 (using the arithmetic sequence properties) and<br />

this led him to deduce that -3 multiplied by -4 is 12.<br />

Arnauld would clearly object to this on the grounds that<br />

Saunderson had started with a decreasing sequence and<br />

yet ended up after multiplication with an increasing<br />

sequence. The ordering principle had been violated.<br />

At the end <strong>of</strong> the day, the three mathematicians make<br />

different assumptions; perhaps Euler and Saunderson are<br />

prepared to go further than Arnauld and that is where the<br />

fundamental difference lies.

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