history of mathematics - National STEM Centre
history of mathematics - National STEM Centre
history of mathematics - National STEM Centre
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14 Answers<br />
<strong>of</strong> multiplication by negative numbers when the<br />
inequality must be reversed. So if a < b and we multiply<br />
both sides <strong>of</strong> the inequality by c < 0, then aobc. You<br />
know that you have to reverse the inequality when you<br />
multiply by a negative number. This means that there is<br />
no contradiction in the rules <strong>of</strong> multiplication when they<br />
are applied to negative numbers as Arnauld suggests.<br />
Activity 10.11, page 131<br />
1 a Lists <strong>of</strong> assumptions<br />
Euler<br />
• assumes that the outcome <strong>of</strong> multiplying together two<br />
numbers is not affected by the order in which we take<br />
the two numbers<br />
• models a negative number as a debt and uses obvious<br />
properties <strong>of</strong> debts to infer properties <strong>of</strong> negative<br />
numbers<br />
• assumes that the product <strong>of</strong> two negative numbers<br />
must be either a positive or a negative number, that is,<br />
it cannot be something new<br />
• assumes that if you take a number and in turn<br />
multiply it by different numbers then the outcome<br />
cannot be the same in both cases<br />
• assumes that when multiplying two numbers together<br />
it is possible to calculate the size (absolute value) <strong>of</strong><br />
the product by multiplying together the sizes<br />
(absolute values) <strong>of</strong> the individual numbers.<br />
Saunderson<br />
• assumes that you can establish that numbers are in<br />
arithmetic progression if there are three or more <strong>of</strong><br />
them to consider<br />
• assumes that if you know the first two terms <strong>of</strong> an<br />
arithmetic progression, then the third can easily be<br />
found<br />
• assumes that if all the terms in an arithmetic<br />
progression are multiplied by the same factor then the<br />
resultant terms (taken in the same order) will also<br />
form an arithmetic progression<br />
• assumes that, even though you might start with an<br />
arithmetic progression with decreasing terms, having<br />
multiplied each by the same factor then the outcome<br />
may be a progression with increasing terms, or vice<br />
versa.<br />
b Arnauld's objections to negative numbers are<br />
summarised below to inform the debate. Arnauld's<br />
objection relates fundamentally to ratios <strong>of</strong> numbers. He<br />
believes that 1 is to a what b is to ab. In other words he<br />
believes that 1 : a is equivalent to b : ab. Examples are:<br />
1 : 3 is equivalent to 4:12;<br />
180<br />
1 : \ is equivalent to -5-: -^.<br />
But he does not believe that 1: - 4 is equivalent to<br />
-5:20.<br />
The reason he gives is that 1 and - 4 cannot be in the<br />
same ratio as -5 and 20 because 1 > -4 whereas<br />
-5 < 20. On that basis alone he disbelieves the rule for<br />
multiplying negative numbers together.<br />
How might a debate between Euler and Arnauld have<br />
been played out on the basis <strong>of</strong> the extracts? It all<br />
depends on the different assumptions that each makes<br />
about operations <strong>of</strong> numbers.<br />
Presumably Arnauld would be prepared to accept that<br />
1: - 3 is equivalent to 4 : - 12 since his ordering<br />
principle applies. In a debate Arnauld could be persuaded<br />
to accept that —b multiplied by a (where a and b are both<br />
positive) produces a negative result. However he would<br />
not accept that 1 : 4 is equivalent to -3: -12 since this<br />
violates the ordering principle, and thus presumably<br />
would not accept that a multiplied by -b is valid.<br />
This logically means that Arnauld cannot accept that a<br />
times —b is the same as —b times a.<br />
On the other hand Euler assumes that the order in which<br />
you multiply a positive by a negative number does not<br />
affect the outcome. A debate between Euler and Arnauld<br />
could centre on this difference <strong>of</strong> opinion with one trying<br />
to convince the other <strong>of</strong> his view. Euler could be made to<br />
justify his assumption. This might be the chink in Euler's<br />
or Arnauld's armour.<br />
Saunderson and Arnauld have more obvious differences<br />
<strong>of</strong> opinion. Saunderson considers numbers in arithmetic<br />
progression; for example, the decreasing sequence 3, 0,<br />
-3. By multiplying each <strong>of</strong> the numbers in the sequence<br />
by - 4 say, he assumes we get another sequence which<br />
starts with -12,0. The third member <strong>of</strong> the sequence<br />
must be 12 (using the arithmetic sequence properties) and<br />
this led him to deduce that -3 multiplied by -4 is 12.<br />
Arnauld would clearly object to this on the grounds that<br />
Saunderson had started with a decreasing sequence and<br />
yet ended up after multiplication with an increasing<br />
sequence. The ordering principle had been violated.<br />
At the end <strong>of</strong> the day, the three mathematicians make<br />
different assumptions; perhaps Euler and Saunderson are<br />
prepared to go further than Arnauld and that is where the<br />
fundamental difference lies.