The thorny way of truth - Free Energy Community

185 -constructive units of the rest of nuclei.In the second column, after the name of the nucleus, is given the number of theprotons, marked with Z; the third column presents the mass number of the nucleus A, andthe fourth column shows the composition of the nucleus (protons and neutron). Next followsthe EES, defined after formula (4), and then its twofold value (both in thousandths_ 10 -97 97of fm, 10 m), where we have worked with m = 1.673x10* kg and m = 1.675x10' kg.for the mass of the proton and neutron, respectively. The seventh column presents thestability, expressed by the half-life period, in the cases of unstable nuclei. The lastcolumn shows which EES of the clusters, of which the nucleus eventually consists, arecontained in the twoflold EES of the investigated nucleus a whole number of times, whatis the condition for stability. It is shown for the unstable ones that they cannot containa whole number of times of EES of the stable nuclei, of which they may be composed.Thus Ip in the last column on the line of the deufron shows that the twofold EES of dcontains one EES of proton or, all the same, one its elementary wave of de Broglie.0.67p and 1.34d on the line of the triton mean that in its twofold EES, the EES of theproton enters 0.67 times and that of the deul^on 1.34 times.The proton stays rather aside - it is the basic constructive unit. Exactly one protonEES enters the twofold EES of the deuteron: it is stable. The triton, which can consistsonly of proton or deuteron, does not contain in its twofold EES a whole number of timesof EES either of proton or of deuteron- and it is unstable, indeed.In the next table (Table 2) we have picked out the EES of those relatively not quitecomplicated stable nuclei which confirm the above stated assumption.At first sight Table 2 shows that the requirement, the width of the potential hole tobe proportional to a whole number of times of elementary wavelengths of de Broglie ofthe stable clusters eventually composing the nucleus, is valid for a great number ofnuclei. The first two ( He and Li) are of a sufficiently simple structure and, therefore,one can easily estimate of which clusters they may be composed, since here few or evenno variations in the choice of the components are possible (if we assume that these clustersmay be the most simple stable nuclei). For C and N, there is a new aspect:12It IS equally possible C, which consists of 6p and 6n, to be constructed either