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The thorny way of truth - Free Energy Community

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'^- 20 - ^**MarinovneitherThus I am inclined to conclude that, the pushing force acting on a II- form bridge,nor the force acting on a U-form bridge can be calculated mathematically. Andtaking into account the negative result <strong>of</strong> my experiment presented in figs. 3 and 4, Imake the general conclusion: the pushing force acting on the Ampere bridge does notdepend on its form. This conclusion, <strong>of</strong> course, has to be confirmed by careful experimentswith U-form and 11- form bridges with very long legs, to see whether, indeed, thepushing forces will be equal. <strong>The</strong>n I think that the pushing force will depend neitheron the size <strong>of</strong> the bridge.*-<strong>The</strong> pushing force acting on the Ampere bridge can be found also proceeding from theformula for the inductance <strong>of</strong> the loop: If L is the inductance <strong>of</strong> the circuit, then themagnetic energy <strong>of</strong> the circuit when current I flows through it is''(p. 363). ^ W = (1/2)LI^. (20)<strong>The</strong> force acting on the circuit at change <strong>of</strong> its characteristic size, a, will bef = 8W/3a = (l/2)I^(8L/aa). (21)<strong>The</strong> inductance <strong>of</strong> a square loop with side a and radius r <strong>of</strong> the wire is^ 'k«..,v.« square= 8xl0'^a{ln(2a/r) + r/Jr^ln(l + v^) - 7/4} = 8xl0"^a{in(2a/r) + r/a - 1.217},(22)while the inductance <strong>of</strong> a circle with diameter a and radius <strong>of</strong> the wire r is^'(p. 361)"-circle " 27Txlo"^a{ln(2a/r) + ln2 - 7/4} = 6.28xl0"^a{ln(2a/r) - 1.057), (23)and we can accept ^L /9a = ^L• , /9a = Const. This conclusion can serve as a mathematicalconfirmation <strong>of</strong> the assertion that the pushing force on the Ampere bridge dependsneither on its form nor on its size. (N.B. According to me, the term "r/a" in formula(22) is due to wrong calculation.)I should like to note the <strong>way</strong> on which one comes to formula (21):<strong>The</strong> magnetic flux * produced by a circuit with inductance L is^^^ (p. 354)* = LI,(24)and as at the motion <strong>of</strong> the Ampere bridge the induced back tension willbe U^^^^ = d

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