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The thorny way of truth - Free Energy Community

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- 224 - PHYSICS LETTERS ARef. No. V 1280 aOBJECTIONS OF STEFAN MARINOV TO THE REFEREE'S COMMENTS ONMARINOV'S PAPER "CALCULATION OF THE PUSHING FORCE WHICH ACTS ON THEAMPEREBRIDGE"I find alj[ referee's objections UNTENABLE. Here are the pro<strong>of</strong>s <strong>of</strong> my assertion.1. <strong>The</strong> referee writes that he cannot understand how formula (1) is derived, as reference1 is not available. <strong>The</strong> derivation <strong>of</strong> formula (1) is a problem which EVERY STUDENTcan solve in three minutes. Indeed, let us have a n-form Ampere bridge with legs <strong>of</strong>lengths L and shoulder <strong>of</strong> length a. Let us take a plane reference frame xOy with origin at the left corner <strong>of</strong> the bridge, with abscissa along the shoulder and with ordinate'directed oppositely to the left leg. At a point on the shoulder, distant x from the origin,a current I in the left Teg (which I assume flowing towards the shoulder) will generate,according to the definition <strong>of</strong> the magnetic potential , the following magnetic poitential .A = l{Moldr/Avr)9, (A)where r is the distance between the current element dr along the leg to the point on theishoulder distant x from the frame's origin. As dr = dy, r = (x2 + y2)l/2^ v^e obtainA = (MoI/4tt)/(x^ + y^)'^^^dyy = (MQl/4TT)Ars1nh(L/x) y. (B)Grassmann's formula for the force with which a current element I'dr' acts on a currentelement Idr, when the distance between them is r (pointing from dr' to dr),is the folloW'ing one -df = (yQir/4TTr-^)dry(dr'xr) = Idrxrot(yQrdr'/4TTr) = Idrxrot(dA). (C)Grassmann's formula can be found in any textbook published before WWI and in one <strong>of</strong>77 textbooks published after WWII (according to my statistics). Any student can in oneminute deduce Grassmann's formula from the Lorentz equation which can be found in anytextbook on electromagnetism published before, between and after the world wars.For the force with which a wire with length L acts on the current element Idr we haveto substitute dA in (C) by A taken from (B), writing Idr = I dxx. After integration forao ^ X ^ a, where ao is a very small quantity, as for ao = there is a singularity, weobtain for the net force acting on the whole bridge, taking into account that there aretwo legs,f = 2/IdxxxrotA = (vi^l2/2TT)/L(x2 + L^)'^''^dx/x)y = (^^1^/2^) / (dx/x)y = (p^I^/2Tr)ln(^ao a© ao'where, as it can be easily calculated, for a bridge with a/L < 0.33 the approximationleads to an error not bigger than 5%.This the formula (1) from my paper about which the referee is wondering where from itmay come.But if the referee is puzzled by formula (1), I ask him: How he does calculate the foracting on a Il-form Ampere bridge? - <strong>The</strong> answer <strong>of</strong> the referee surely will be: "I do notknow how." Thus the first question <strong>of</strong> the referee reveals the fact that he NEVER has calculatedand NEVER has seen the analytical expression <strong>of</strong> the force acting on a n-form Amperebridge. Indeed, formula (1) can be found in NO textbook on electromagnetism allover the world, as it CLEARLY SHOWS that the Ampere bridge moves by the action <strong>of</strong> internaforces and it thus PATENTLY VIOLATES Newton's third law. I am asking the referee: "Is,according to him, the Ampere bridge violating Newton's third law?", but I know with suretthat the referee will be AFRAID to give an answer to this question.

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