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Callister - An introduction - 8th edition

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7.12 Recrystallization • 223<br />

DESIGN EXAMPLE 7.1<br />

Description of Diameter Reduction Procedure<br />

A cylindrical rod of noncold-worked brass having an initial diameter of 6.4 mm<br />

(0.25 in.) is to be cold worked by drawing such that the cross-sectional area is<br />

reduced. It is required to have a cold-worked yield strength of at least 345 MPa<br />

(50,000 psi) and a ductility in excess of 20%EL; in addition, a final diameter of<br />

5.1 mm (0.20 in.) is necessary. Describe the manner in which this procedure may<br />

be carried out.<br />

Solution<br />

Let us first consider the consequences (in terms of yield strength and ductility) of<br />

cold working in which the brass specimen diameter is reduced from 6.4 mm (designated<br />

by d 0 ) to 5.1 mm (d i ). The %CW may be computed from Equation 7.8 as<br />

%CW <br />

<br />

a d 0<br />

2 b 2<br />

p a d i<br />

2 b 2<br />

p<br />

a<br />

a d 0<br />

2 b 2<br />

p<br />

6.4 mm<br />

b<br />

2<br />

a<br />

2p a<br />

2<br />

6.4 mm<br />

b p<br />

2<br />

100<br />

2<br />

5.1 mm<br />

b p<br />

2<br />

100 36.5%CW<br />

From Figures 7.19a and 7.19c, a yield strength of 410 MPa (60,000 psi) and a ductility<br />

of 8%EL are attained from this deformation. According to the stipulated<br />

criteria, the yield strength is satisfactory; however, the ductility is too low.<br />

<strong>An</strong>other processing alternative is a partial diameter reduction, followed by<br />

a recrystallization heat treatment in which the effects of the cold work are nullified.<br />

The required yield strength, ductility, and diameter are achieved through<br />

a second drawing step.<br />

Again, reference to Figure 7.19a indicates that 20%CW is required to give a<br />

yield strength of 345 MPa. On the other hand, from Figure 7.19c, ductilities greater<br />

than 20%EL are possible only for deformations of 23%CW or less. Thus during<br />

the final drawing operation, deformation must be between 20%CW and 23%CW.<br />

Let’s take the average of these extremes, 21.5%CW, and then calculate the final<br />

diameter for the first drawing d¿ 0 , which becomes the original diameter for the second<br />

drawing. Again, using Equation 7.8,<br />

a d¿ 2<br />

2<br />

0<br />

2 b 5.1 mm<br />

p a b p<br />

2<br />

21.5%CW <br />

a d¿ 100<br />

2<br />

0<br />

2 b p<br />

Now, solving for d¿ 0 from the preceding expression gives<br />

d¿ 0 5.8 mm 10.226 in.2

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