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RePoSS #11: The Mathematics of Niels Henrik Abel: Continuation ...

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146 Chapter 7. Particular classes <strong>of</strong> solvable equations<br />

Obviously, the form <strong>of</strong> the right hand side shows that this expression was a rational<br />

function <strong>of</strong> x. ABEL stated that it was unaffected by substituting θ m (x) for x and<br />

considered it so obvious that he did not provide the details. 5 Thus, the expression<br />

was a rational function <strong>of</strong> the coefficients <strong>of</strong> φ (x) = 0; ABEL denoted this function by<br />

a k,<br />

µ√<br />

vk = ak ( µ√ v1) k .<br />

v1<br />

ABEL stated the conclusion <strong>of</strong> this investigation by giving an algebraic formula for<br />

the root x, 6<br />

x = 1<br />

�<br />

−A +<br />

µ<br />

µ√ v1 + a2<br />

(<br />

v1<br />

µ√ v1) 2 + a3<br />

(<br />

v1<br />

µ√ v1) 3 + · · · + aµ−1<br />

(<br />

v1<br />

µ√ v1) µ−1<br />

�<br />

. (7.10)<br />

All the other roots were contained in this formula by giving µ√ v1 its µ different values<br />

α k µ √ v1. ABEL expressed the implications for solubility in two theorems capturing the<br />

essence <strong>of</strong> this research. If the set <strong>of</strong> roots fell into one “orbit” <strong>of</strong> the rational expres-<br />

sion, θ, ABEL found the equation to be solvable by radicals:<br />

<strong>The</strong>orem 6 “If the roots <strong>of</strong> an algebraic equation can be represented by:<br />

x, θx, θ 2 x, . . . θ µ−1 x,<br />

where θ µ x = x and θx denotes a rational function <strong>of</strong> x and known quantities, this equation<br />

will always be algebraically solvable.” 7<br />

Applying this result to the particular case <strong>of</strong> irreducible equations <strong>of</strong> prime degree,<br />

which always had only one chain, ABEL found that such equations were algebraically<br />

solvable:<br />

“If two roots <strong>of</strong> an irreducible equation, <strong>of</strong> which the degree is a prime number,<br />

have such a relation that one can express the one rationally in the other, this<br />

equation will be algebraically solvable.” 8<br />

Subsequently, ABEL refined the hypothesis that all the roots could be expressed as<br />

iterations <strong>of</strong> a rational function. That hypothesis had ensured algebraic solubility <strong>of</strong><br />

the equation, but the same conclusion could also be established for a broader class <strong>of</strong><br />

equations. Under the general assumption that every root <strong>of</strong> an equation, χ (x) = 0,<br />

5 <strong>The</strong> details can easily be provided by inserting into the right hand side and rearranging terms.<br />

6 (N. H. <strong>Abel</strong>, 1829c, 142).<br />

7 “Si les racines d’une équation algébrique peuvent être représentées par:<br />

x, θx, θ 2 x, . . . θ µ−1 x,<br />

où θ µ x = x et θx désigne une fonction rationelle de x et de quantités connues, cette équation sera<br />

toujours résoluble algébriquement.” (ibid., 142–143).<br />

8 “Si deux racines d’une équation irréductible, dont le degré est un nombre premier, sont dans un<br />

tel rapport, qu’on puisse exprimer l’une rationnellement par l’autre, cette équation sera résoluble<br />

algébriquement.” (ibid., 143).

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