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RePoSS #11: The Mathematics of Niels Henrik Abel: Continuation ...

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19.2. <strong>The</strong> contents <strong>of</strong> ABEL’s Paris result and its pro<strong>of</strong> 359<br />

Linear interdependence <strong>of</strong> q0, . . . , qn−1 In order to see how ABEL obtained the linear<br />

interrelations among the coefficients <strong>of</strong> θ (y), we notice from combining the factoriza-<br />

tion (19.5) with the definition <strong>of</strong> r (19.4),<br />

r (x) = F (x) · F0 (x)<br />

=<br />

n<br />

∏ θ<br />

k=1<br />

�<br />

y (k) (x)<br />

�<br />

=<br />

n n−1<br />

∏ ∑<br />

k=1 m=0<br />

�<br />

qm (x) y (k) �m (x) .<br />

Thus, since r (β1) = F (β1) · 0 = 0, some k must exist for which θ<br />

n−1 �<br />

∑ qm (x) y<br />

m=0<br />

(k) �m (x) = 0.<br />

�<br />

y (k) �<br />

(β1) = 0, i.e.<br />

This relation is a linear interdependence among the q0, . . . , qn−1 in which the<br />

here serving as coefficients, are functions <strong>of</strong> x.<br />

Box 10: Linear interdependence <strong>of</strong> q0, . . . , qn−1<br />

�<br />

y (k)� m<br />

,<br />

ABEL’S way <strong>of</strong> proving f (x, y) χ ′ (y) to be an entire function. ABEL’S investiga-<br />

tions leading to the result that f (x, y) χ ′ (y) was an entire function progressed along<br />

complicated and tedious arguments. At the very outset <strong>of</strong> the paper, ABEL had split<br />

the rational function <strong>of</strong> x in the following way<br />

f (x, y) χ ′ (y) = f1 (x, y)<br />

, (19.16)<br />

f2 (x)<br />

where f2 (x) was an entire function <strong>of</strong> x independent <strong>of</strong> y. By combining this with the<br />

important partial differentiation (19.7), ABEL found<br />

f (x, y) dx =<br />

f1 (x, y)<br />

f2 (x) · χ ′ (y) dx<br />

1<br />

= −<br />

F0 (x) · F ′ (x) · f2 (x)<br />

n<br />

∑<br />

k=1<br />

f1 (x, y k)<br />

χ ′ (y k)<br />

r<br />

θ (y k) ∂θ (y k) .<br />

Later, during his investigations leading to the Main <strong>The</strong>orem I, ABEL had studied the<br />

function<br />

which he had chosen to write as<br />

f1 (x, y)<br />

f1 (x, y)<br />

r<br />

∂θ (y)<br />

θ (y)<br />

r<br />

θ (y) ∂θ (y) = R′ (y) + R (x) y n−1 ,<br />

where R ′ (y) indicated an entire function <strong>of</strong> x and y in which no powers <strong>of</strong> y beyond<br />

the (n − 2)’nd occur, and R (x) was an entire function <strong>of</strong> x independent <strong>of</strong> y. By use <strong>of</strong>

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