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RePoSS #11: The Mathematics of Niels Henrik Abel: Continuation ...

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7.1. Solubility <strong>of</strong> <strong>Abel</strong>ian equations 151<br />

1) <strong>The</strong> division <strong>of</strong> the whole circle into n − 1 parts (n − 1 because the irreducible<br />

= 0),<br />

equation in GAUSS’ research was xn −1<br />

x−1<br />

2) <strong>The</strong> division into n − 1 parts <strong>of</strong> another arc which could be constructed after step<br />

1 had been completed, and<br />

3) <strong>The</strong> extraction <strong>of</strong> a square root.<br />

<strong>The</strong> final step, the extraction <strong>of</strong> a square root, could be assumed to equal the construc-<br />

tion <strong>of</strong> √ n, GAUSS claimed without providing any pro<strong>of</strong>. Later, ABEL adopted and<br />

proved the assertion.<br />

In the fifth section <strong>of</strong> the Mémoire sur une classe particulière, ABEL applied his theory<br />

directly to the cyclotomic equation and the circular functions related to the division <strong>of</strong><br />

the circle. By the addition formulae for cosine, ABEL could express cos ma rationally<br />

in cos a, and assuming θ (cos a) = cos ma and θ1 (cos a) = cos m ′ a, he obtained<br />

θθ1 (x) = θ � cos m ′ a � = cos � mm ′ a �<br />

= cos � m ′ ma � = θ1 (cos ma) = θ1θ (x) .<br />

From a previously established result (here theorem 7), ABEL found that cos 2π µ could<br />

be determined algebraically — which was a well known result.<br />

ABEL, however, did not stop his investigations <strong>of</strong> the circular functions at this<br />

point, as he might have done had he only been interested in the algebraic solubility <strong>of</strong><br />

the division. Assuming that µ = 2n + 1 was prime, ABEL studied the equation<br />

and used the rational dependency established above<br />

to write<br />

n �<br />

∏ X − cos<br />

k=1<br />

2kπ<br />

�<br />

= 0, (7.14)<br />

2n + 1<br />

θ (cos a) = cos ma<br />

θ k (cos a) = cos m k a.<br />

By an argument based on GAUSS’ primitive roots <strong>of</strong> the module 2n + 1, ABEL demon-<br />

strated that the roots <strong>of</strong> (7.14) were<br />

x, θ (x) , θ 2 (x) , . . . , θ n−1 (x) where θ n (x) = x.<br />

<strong>The</strong>refore, the equation (7.14) was algebraically solvable by ABEL’S third theorem<br />

(here theorem 6), and ABEL adapted theorem 8 to this particular equation, obtain-<br />

ing the same result as GAUSS had found. Furthermore, ABEL presented a pro<strong>of</strong> <strong>of</strong><br />

the result, which GAUSS had only announced, that the square root extracted in step 3<br />

could always be made to equal √ 2n + 1 (in ABEL’S variables).<br />

<strong>The</strong> contents <strong>of</strong> ABEL’S Mémoire sur une classe particulière can be summarized in the<br />

following five points depicting a descent from the general to the particular:

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