fundamentals of engineering supplied-reference handbook - Ventech!
fundamentals of engineering supplied-reference handbook - Ventech!
fundamentals of engineering supplied-reference handbook - Ventech!
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People Requirements<br />
n PijTij<br />
Aj<br />
= ∑ , where<br />
= 1 C<br />
i ij<br />
Aj = number <strong>of</strong> crews required for assembly operation j,<br />
Pij = desired production rate for product i and assembly<br />
operation j (pieces per day),<br />
Tij = standard time to perform operation j on product i<br />
(minutes per piece),<br />
Cij = number <strong>of</strong> minutes available per day for assembly<br />
operation j on product i, and<br />
n = number <strong>of</strong> products.<br />
Standard Time Determination<br />
ST = NT × AF<br />
where<br />
NT = normal time, and<br />
AF = allowance factor.<br />
Case 1: Allowances are based on the job time.<br />
AFjob = 1 + Ajob<br />
Ajob = allowance fraction (percentage) based on job time.<br />
Case 2: Allowances are based on workday.<br />
AFtime = 1/(1 – Aday)<br />
Aday = allowance fraction (percentage) based on workday.<br />
Plant Location<br />
The following is one formulation <strong>of</strong> a discrete plant location<br />
problem.<br />
Minimize<br />
= ∑∑+ ∑<br />
m n<br />
n<br />
z c y f x<br />
subject to<br />
m<br />
i=<br />
1<br />
n<br />
j=<br />
1<br />
ij ij<br />
i=<br />
1 j=<br />
1<br />
j=<br />
1<br />
∑ y ≤ mx , j = 1, …,<br />
n<br />
ij<br />
ij<br />
j<br />
∑ y = 1, i = 1, …,<br />
m<br />
j<br />
m =<br />
yij ≥ 0, for all i, j<br />
xj = (0, 1), for all j, where<br />
number <strong>of</strong> customers,<br />
n = number <strong>of</strong> possible plant sites,<br />
yij = fraction or portion <strong>of</strong> the demand <strong>of</strong> customer i<br />
which is satisfied by a plant located at site j; i = 1,<br />
…, m; j = 1, …, n,<br />
xj = 1, if a plant is located at site j,<br />
xj = 0, otherwise,<br />
cij = cost <strong>of</strong> supplying the entire demand <strong>of</strong> customer i<br />
from a plant located at site j, and<br />
fj = fixed cost resulting from locating a plant at site j.<br />
j<br />
195<br />
INDUSTRIAL ENGINEERING (continued)<br />
Material Handling<br />
Distances between two points (x1, y1) and (x1, y1) under<br />
different metrics:<br />
Euclidean:<br />
( ) ( ) 2<br />
2<br />
x − x + y y<br />
D =<br />
−<br />
1<br />
2<br />
1<br />
Rectilinear (or Manhattan):<br />
D = ⏐x1 – x2⏐ + ⏐y1 – y2⏐<br />
Chebyshev (simultaneous x and y movement):<br />
D = max(⏐x1 – x2⏐ , ⏐y1 – y2⏐)<br />
Line Balancing<br />
⎛<br />
⎞<br />
Nmin = ⎜OR<br />
× ∑ti<br />
OT ⎟<br />
⎝ i ⎠<br />
= Theoretical minimum number <strong>of</strong> stations<br />
Idle Time/Station = CT – ST<br />
Idle Time/Cycle = Σ (CT – ST)<br />
Idle Time Cycle<br />
Percent Idle Time = × 100 , where<br />
N × CT<br />
actual<br />
CT = cycle time (time between units),<br />
OT = operating time/period,<br />
OR = output rate/period,<br />
ST = station time (time to complete task at each station),<br />
ti = individual task times, and<br />
N = number <strong>of</strong> stations.<br />
Job Sequencing<br />
Two Work Centers—Johnson's Rule<br />
1. Select the job with the shortest time, from the list <strong>of</strong><br />
jobs, and its time at each work center.<br />
2. If the shortest job time is the time at the first work<br />
center, schedule it first, otherwise schedule it last. Break<br />
ties arbitrarily.<br />
3. Eliminate that job from consideration.<br />
4. Repeat 1, 2, and 3 until all jobs have been scheduled.<br />
CRITICAL PATH METHOD (CPM)<br />
dij = duration <strong>of</strong> activity (i, j),<br />
CP = critical path (longest path),<br />
T = duration <strong>of</strong> project, and<br />
( ) ∑ = T<br />
dij<br />
i,<br />
j ∈CP<br />
2