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People Requirements<br />

n PijTij<br />

Aj<br />

= ∑ , where<br />

= 1 C<br />

i ij<br />

Aj = number <strong>of</strong> crews required for assembly operation j,<br />

Pij = desired production rate for product i and assembly<br />

operation j (pieces per day),<br />

Tij = standard time to perform operation j on product i<br />

(minutes per piece),<br />

Cij = number <strong>of</strong> minutes available per day for assembly<br />

operation j on product i, and<br />

n = number <strong>of</strong> products.<br />

Standard Time Determination<br />

ST = NT × AF<br />

where<br />

NT = normal time, and<br />

AF = allowance factor.<br />

Case 1: Allowances are based on the job time.<br />

AFjob = 1 + Ajob<br />

Ajob = allowance fraction (percentage) based on job time.<br />

Case 2: Allowances are based on workday.<br />

AFtime = 1/(1 – Aday)<br />

Aday = allowance fraction (percentage) based on workday.<br />

Plant Location<br />

The following is one formulation <strong>of</strong> a discrete plant location<br />

problem.<br />

Minimize<br />

= ∑∑+ ∑<br />

m n<br />

n<br />

z c y f x<br />

subject to<br />

m<br />

i=<br />

1<br />

n<br />

j=<br />

1<br />

ij ij<br />

i=<br />

1 j=<br />

1<br />

j=<br />

1<br />

∑ y ≤ mx , j = 1, …,<br />

n<br />

ij<br />

ij<br />

j<br />

∑ y = 1, i = 1, …,<br />

m<br />

j<br />

m =<br />

yij ≥ 0, for all i, j<br />

xj = (0, 1), for all j, where<br />

number <strong>of</strong> customers,<br />

n = number <strong>of</strong> possible plant sites,<br />

yij = fraction or portion <strong>of</strong> the demand <strong>of</strong> customer i<br />

which is satisfied by a plant located at site j; i = 1,<br />

…, m; j = 1, …, n,<br />

xj = 1, if a plant is located at site j,<br />

xj = 0, otherwise,<br />

cij = cost <strong>of</strong> supplying the entire demand <strong>of</strong> customer i<br />

from a plant located at site j, and<br />

fj = fixed cost resulting from locating a plant at site j.<br />

j<br />

195<br />

INDUSTRIAL ENGINEERING (continued)<br />

Material Handling<br />

Distances between two points (x1, y1) and (x1, y1) under<br />

different metrics:<br />

Euclidean:<br />

( ) ( ) 2<br />

2<br />

x − x + y y<br />

D =<br />

−<br />

1<br />

2<br />

1<br />

Rectilinear (or Manhattan):<br />

D = ⏐x1 – x2⏐ + ⏐y1 – y2⏐<br />

Chebyshev (simultaneous x and y movement):<br />

D = max(⏐x1 – x2⏐ , ⏐y1 – y2⏐)<br />

Line Balancing<br />

⎛<br />

⎞<br />

Nmin = ⎜OR<br />

× ∑ti<br />

OT ⎟<br />

⎝ i ⎠<br />

= Theoretical minimum number <strong>of</strong> stations<br />

Idle Time/Station = CT – ST<br />

Idle Time/Cycle = Σ (CT – ST)<br />

Idle Time Cycle<br />

Percent Idle Time = × 100 , where<br />

N × CT<br />

actual<br />

CT = cycle time (time between units),<br />

OT = operating time/period,<br />

OR = output rate/period,<br />

ST = station time (time to complete task at each station),<br />

ti = individual task times, and<br />

N = number <strong>of</strong> stations.<br />

Job Sequencing<br />

Two Work Centers—Johnson's Rule<br />

1. Select the job with the shortest time, from the list <strong>of</strong><br />

jobs, and its time at each work center.<br />

2. If the shortest job time is the time at the first work<br />

center, schedule it first, otherwise schedule it last. Break<br />

ties arbitrarily.<br />

3. Eliminate that job from consideration.<br />

4. Repeat 1, 2, and 3 until all jobs have been scheduled.<br />

CRITICAL PATH METHOD (CPM)<br />

dij = duration <strong>of</strong> activity (i, j),<br />

CP = critical path (longest path),<br />

T = duration <strong>of</strong> project, and<br />

( ) ∑ = T<br />

dij<br />

i,<br />

j ∈CP<br />

2

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