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fundamentals of engineering supplied-reference handbook - Ventech!

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The deflection θ and moment Fr are related by<br />

Fr = kθ<br />

where the spring rate k is given by<br />

4<br />

d E<br />

k =<br />

64DN<br />

where k has units <strong>of</strong> N·m/rad and θ is in radians.<br />

Spring Material: The strength <strong>of</strong> the spring wire may be<br />

found as shown in the section on linear springs. The<br />

allowable stress σ is then given by<br />

Sy = σ = 0.78Sut cold-drawn carbon steel (A227,<br />

A228, A229)<br />

Sy = σ = 0.87Sut hardened and tempered carbon<br />

and low-alloy steel (A232, A401)<br />

Ball/Roller Bearing Selection<br />

The minimum required basic load rating (load for which<br />

90% <strong>of</strong> the bearings from a given population will survive 1<br />

million revolutions) is given by<br />

1<br />

a<br />

C = PL , where<br />

C = minimum required basic load rating,<br />

P = design radial load,<br />

L = design life (in millions <strong>of</strong> revolutions), and<br />

a = 3 for ball bearings, 10/3 for roller bearings.<br />

When a ball bearing is subjected to both radial and axial<br />

loads, an equivalent radial load must be used in the<br />

equation above. The equivalent radial load is<br />

Peq = XVFr + YFa, where<br />

Peq = equivalent radial load,<br />

Fr = applied constant radial load, and<br />

Fa = applied constant axial (thrust) load.<br />

For radial contact, deep-groove ball bearings:<br />

V = 1 if inner ring rotating, 1.2 if outer ring rotating,<br />

If Fa /(VFr) > e,<br />

X = 0.<br />

56,<br />

where<br />

and<br />

⎛ Fa<br />

⎞<br />

e = 0.<br />

513⎜<br />

⎟<br />

⎜ C ⎟<br />

⎝ o ⎠<br />

⎛ Fa<br />

⎞<br />

Y = 0.<br />

840⎜<br />

⎟<br />

⎜ C ⎟<br />

⎝ o ⎠<br />

0.<br />

236<br />

,<br />

and<br />

−0.<br />

247<br />

Co = basic static load rating, from bearing catalog.<br />

If Fa /(VFr) ≤ e, X = 1 and Y = 0.<br />

204<br />

MECHANICAL ENGINEERING (continued)<br />

Intermediate- and Long-Length Columns<br />

The slenderness ratio <strong>of</strong> a column is Sr = l/k, where l is the<br />

length <strong>of</strong> the column and k is the radius <strong>of</strong> gyration. The<br />

radius <strong>of</strong> gyration <strong>of</strong> a column cross-section is, k = I A<br />

where I is the area moment <strong>of</strong> inertia and A is the crosssectional<br />

area <strong>of</strong> the column. A column is considered to be<br />

intermediate if its slenderness ratio is less than or equal to<br />

(Sr)D, where<br />

2E<br />

S<br />

( S ) = π , and<br />

r<br />

D<br />

y<br />

E = Young's modulus <strong>of</strong> respective member, and<br />

Sy = yield strength <strong>of</strong> the column material.<br />

For intermediate columns, the critical load is<br />

⎡<br />

2<br />

1 ⎛ S ⎤<br />

yS<br />

r ⎞<br />

P ⎢ ⎜ ⎟ ⎥<br />

cr = A S y −<br />

⎢<br />

⎜ ⎟<br />

, where<br />

E ⎥<br />

⎣ ⎝ 2π<br />

⎠ ⎦<br />

Pcr = critical buckling load,<br />

A = cross-sectional area <strong>of</strong> the column,<br />

Sy = yield strength <strong>of</strong> the column material,<br />

E = Young's modulus <strong>of</strong> respective member, and<br />

Sr = slenderness ratio.<br />

For long columns, the critical load is<br />

P<br />

cr<br />

2<br />

π EA<br />

=<br />

S<br />

2<br />

r<br />

where the variables are as defined above.<br />

For both intermediate and long columns, the effective<br />

column length depends on the end conditions. The AISC<br />

recommended values for the effective lengths <strong>of</strong> columns<br />

are, for: rounded-rounded or pinned-pinned ends, leff = l;<br />

fixed-free, leff = 2.1l; fixed-pinned, leff = 0.80l; fixed-fixed,<br />

leff = 0.65l. The effective column length should be used<br />

when calculating the slenderness ratio.<br />

Power Transmission<br />

Shafts and Axles<br />

Static Loading: The maximum shear stress and the von<br />

Mises stress may be calculated in terms <strong>of</strong> the loads from<br />

2<br />

2 2 1 2<br />

τ max = [ ( 8M<br />

+ Fd ) + ( 8T<br />

) ] ,<br />

3<br />

πd<br />

[ ( ) ] 2 1<br />

4<br />

2 2<br />

σ′ = 8M<br />

+ Fd + 48T<br />

, where<br />

3<br />

πd<br />

M = the bending moment,<br />

F = the axial load,<br />

T = the torque, and<br />

d = the diameter.

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