fundamentals of engineering supplied-reference handbook - Ventech!
fundamentals of engineering supplied-reference handbook - Ventech!
fundamentals of engineering supplied-reference handbook - Ventech!
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Gibbs Phase Rule<br />
P + F = C + 2, where<br />
P = number <strong>of</strong> phases making up a system,<br />
F = degrees <strong>of</strong> freedom, and<br />
C = number <strong>of</strong> components in a system.<br />
BINARY PHASE DIAGRAMS<br />
Allows determination <strong>of</strong> (1) what phases are present at<br />
equilibrium at any temperature and average composition, (2)<br />
the compositions <strong>of</strong> those phases, and (3) the fractions <strong>of</strong><br />
those phases.<br />
Eutectic reaction (liquid → two solid phases)<br />
Eutectoid reaction (solid → two solid phases)<br />
Peritectic reaction (liquid + solid → solid)<br />
Pertectoid reaction (two solid phases → solid)<br />
Lever Rule<br />
The following phase diagram and equations illustrate how<br />
the weight <strong>of</strong> each phase in a two-phase system can be<br />
determined:<br />
(In diagram, L = liquid) If x = the average composition at<br />
temperature T, then<br />
xβ<br />
− x<br />
wt % α = × 100<br />
xβ<br />
− xα<br />
x − xα<br />
wt % β = × 100<br />
x − x<br />
β<br />
α<br />
59<br />
Iron-Iron Carbide Phase Diagram<br />
•<br />
THERMODYNAMICS (continued)<br />
COMBUSTION PROCESSES<br />
First, the combustion equation should be written and<br />
balanced. For example, for the stoichiometric combustion <strong>of</strong><br />
methane in oxygen:<br />
CH4 + 2 O2 → CO2 + 2 H2O<br />
Combustion in Air<br />
For each mole <strong>of</strong> oxygen, there will be 3.76 moles <strong>of</strong><br />
nitrogen. For stoichiometric combustion <strong>of</strong> methane in air:<br />
CH4 + 2 O2 + 2(3.76) N2 → CO2 + 2 H2O + 7.52 N2<br />
Combustion in Excess Air<br />
The excess oxygen appears as oxygen on the right side <strong>of</strong><br />
the combustion equation.<br />
Incomplete Combustion<br />
Some carbon is burned to create carbon monoxide (CO).<br />
mass <strong>of</strong> air<br />
Air-Fuel Ratio (A/F): A/F =<br />
mass <strong>of</strong> fuel<br />
Stoichiometric (theoretical) air-fuel ratio is the air-fuel ratio<br />
calculated from the stoichiometric combustion equation.<br />
( A F ) actual<br />
Percent Theoretical Air =<br />
× 100<br />
A F<br />
Percent Excess Air =<br />
( )<br />
stoichiometric<br />
( A F ) actual − ( A F )<br />
( A F )<br />
stoichiometric<br />
stoichiometric<br />
× 100<br />
• Van Vlack, L., Elements <strong>of</strong> Materials Science & Engineering, Addison-Wesley<br />
Publishing Co., Inc., 1989.