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fundamentals of engineering supplied-reference handbook - Ventech!

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Gibbs Phase Rule<br />

P + F = C + 2, where<br />

P = number <strong>of</strong> phases making up a system,<br />

F = degrees <strong>of</strong> freedom, and<br />

C = number <strong>of</strong> components in a system.<br />

BINARY PHASE DIAGRAMS<br />

Allows determination <strong>of</strong> (1) what phases are present at<br />

equilibrium at any temperature and average composition, (2)<br />

the compositions <strong>of</strong> those phases, and (3) the fractions <strong>of</strong><br />

those phases.<br />

Eutectic reaction (liquid → two solid phases)<br />

Eutectoid reaction (solid → two solid phases)<br />

Peritectic reaction (liquid + solid → solid)<br />

Pertectoid reaction (two solid phases → solid)<br />

Lever Rule<br />

The following phase diagram and equations illustrate how<br />

the weight <strong>of</strong> each phase in a two-phase system can be<br />

determined:<br />

(In diagram, L = liquid) If x = the average composition at<br />

temperature T, then<br />

xβ<br />

− x<br />

wt % α = × 100<br />

xβ<br />

− xα<br />

x − xα<br />

wt % β = × 100<br />

x − x<br />

β<br />

α<br />

59<br />

Iron-Iron Carbide Phase Diagram<br />

•<br />

THERMODYNAMICS (continued)<br />

COMBUSTION PROCESSES<br />

First, the combustion equation should be written and<br />

balanced. For example, for the stoichiometric combustion <strong>of</strong><br />

methane in oxygen:<br />

CH4 + 2 O2 → CO2 + 2 H2O<br />

Combustion in Air<br />

For each mole <strong>of</strong> oxygen, there will be 3.76 moles <strong>of</strong><br />

nitrogen. For stoichiometric combustion <strong>of</strong> methane in air:<br />

CH4 + 2 O2 + 2(3.76) N2 → CO2 + 2 H2O + 7.52 N2<br />

Combustion in Excess Air<br />

The excess oxygen appears as oxygen on the right side <strong>of</strong><br />

the combustion equation.<br />

Incomplete Combustion<br />

Some carbon is burned to create carbon monoxide (CO).<br />

mass <strong>of</strong> air<br />

Air-Fuel Ratio (A/F): A/F =<br />

mass <strong>of</strong> fuel<br />

Stoichiometric (theoretical) air-fuel ratio is the air-fuel ratio<br />

calculated from the stoichiometric combustion equation.<br />

( A F ) actual<br />

Percent Theoretical Air =<br />

× 100<br />

A F<br />

Percent Excess Air =<br />

( )<br />

stoichiometric<br />

( A F ) actual − ( A F )<br />

( A F )<br />

stoichiometric<br />

stoichiometric<br />

× 100<br />

• Van Vlack, L., Elements <strong>of</strong> Materials Science & Engineering, Addison-Wesley<br />

Publishing Co., Inc., 1989.

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