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FIFTH CANADIAN CONFERENCE ON NONDESTRUCTIVE ... - IAEA

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- 118 -<br />

now _n = Af (5)<br />

n<br />

where Af is the spacing between consecutive frequency maxima which is the<br />

slope of the plot of f vs n.<br />

Plotting 2hfa—ß" vs tan ß wil1 y ield a strai Sht line with<br />

gradient = d COSY (6)<br />

and intercept = d sinY (7)<br />

Thus, the diameter and orientation of the circular scatterer can be found<br />

from<br />

d = \ (gradient 2 + intercept 2 ) (8)<br />

-1 /intercept \<br />

' I gradient /<br />

For d«D, it can be shown from simple trigonometry that<br />

VAt = 2dsine (10)<br />

where At is the difference in round trip travel time between the two opposite<br />

edges of the circular scatterer.<br />

Substituting Eq. (3) into Eq. (10) and rearranging terms<br />

VAt<br />

2 cos<br />

= d cos y tan s + d sin Y<br />

Plotting „ —— vs tan B will yield a straight line with gradient<br />

c. COS p<br />

and intercept again given by Eq. (6) and (7). Thus d and y can be found<br />

from Eq. (8) and Eq. (9).<br />

The methods described above thus show that ultrasonic frequency analysis and<br />

time-of-flight method can independently yield information about d and Y of<br />

a circular scatterer.<br />

Using Eq. (2), (5) and (10), it can be shown that<br />

AtAf ~ 1 (12)

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