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Electrical Power Systems

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158 <strong>Electrical</strong> <strong>Power</strong> <strong>Systems</strong><br />

Q ik = |V i| 2 |Y ik |sin q ik – |V i||V k||Y ik|sin (q ik – d i + d k )<br />

Similarly power flows from bus k to i can be written as:<br />

–|V i| 2 |y o ik | ...(7.35)<br />

P ki = –|V k | 2 |Y ik |cos q ik + |V i ||V k ||Y ik |cos (q ik – d k + d i ) ...(7.36)<br />

Q ki = |V k | 2 |Y ik |sin q ik – |V i ||V k ||Y ik |sin (q ik – d k + d i )<br />

–|Vk | 2 |yo ki | ...(7.37)<br />

Now real power loss in the line (i ® k) is the sum of the real power flows determined from<br />

eqn. (7.34) and (7.36)<br />

\ PLoss ik = P ik + P ki<br />

\ PLoss ik = –|V i | 2 |Y ik |cos q ik +|V i ||V k ||Y ik |cos (q ik – d i + d k )<br />

–|V k | 2 |Y ik |cos q ik +|V i ||V k ||Y ik |cos (q ik – d k + d i )<br />

= – (|V i | 2 +|V k | 2 )|Y ik |cos q ik<br />

+ |V i||V k||Y ik|[ cos { q ik – (d i – d k )} + cos {q ik + (d i – d k )}]<br />

= – (|V i| 2 +|V k| 2 )|Y ik|cos q ik + 2|V i||V k||Y ik|cosq ik cos (d i – d k )<br />

\ PLoss ik = [2|V i||V k|cos (d i – d k ) –|V i| 2 – |V k| 2 ]|Y ik|cosq ik ...(7.38)<br />

Let<br />

Y ik = G ik + jB ik<br />

G ik =|Y ik | cosq ik<br />

B ik =|Y ik | sinq ik<br />

\ PLoss ik = G ik [2|V i||V k|cos (d i – d k ) –|V i| 2 – |V k| 2 ] ...(7.39)<br />

Reactive power loss in the line (i ® k) is the sum of the reactive power flows determined<br />

from eqns. (7.35) and (7.37), i.e.<br />

QLoss ik = Q ik + Q ki<br />

\ QLoss ik = |V i| 2 |Y ik|sin q ik –|V i||V k||Y ik|sin(q ik – d i + d k )<br />

–|V i| 2 |y o ik| +|V k| 2 |Y ik|sinq ik<br />

– |V i||V k||Y ik|sin( q ik – d k + d i ) – |V k| 2 |y o ki|<br />

\ QLoss ik = (|V i| 2 +|V k| 2 ) B ik – |V i||V k||Y ik|[ sin(q ik – d i + d k ) + sin(q ik – d k + d i)]<br />

– (|V i| 2 |y o ik| +|V k| 2 |y o ki|)<br />

\ QLoss ik = (|V i| 2 +|V k| 2 ) B ik – 2|V i||V k| B ik cos (d i – d k ) – (|V i| 2 |y o ik| +|V k| 2 |y o ki|)<br />

\ QLoss ik = B ik [|V i| 2 + |V k| 2 –2|V i||V k|cos ( d i – d k)] – [|V i| 2 |y o ik| +|V k| 2 |y o ki|]<br />

...(7.40)<br />

7.10 ALGORITHM OR GAUSS-SEIDEL METHOD<br />

Step-1: Initial Computation<br />

With the load profile known at each bus (i.e. PL i and QL i are known), allocate Pg i and Qg i to all<br />

generating units. While active and reactive generations are not allocated to the slack bus, these

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