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Electrical Power Systems

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V Ki =<br />

1<br />

pÎ<br />

N<br />

å<br />

q<br />

m<br />

2 o m = 1<br />

3.3 CAPACITANCE O A SINGLE PHASE LINE<br />

<br />

HG<br />

Km<br />

I<br />

KJ<br />

Capacitance of Transmission Lines 55<br />

Dim<br />

ln Volts ...(3.5)<br />

D<br />

igure 3.3 shows a single phase line consisting of two long solid conductors having raidus r 1 and<br />

r 2 respectively. Conductor 1 carries a charge of q 1 coulombs/m and conductor 2 carries a charge<br />

of q 2 coulombs/m. The field of the first conductor is disturbed due to the presence of the second<br />

conductor and the ground. The distance between the conductors is D and D is much greater<br />

than the raddi of the conductors. Also, the height of the conductors from the ground is much<br />

larger than D. Therefore the effect of distortion is negligible and the charge is assumed to be<br />

uniformly distributed.<br />

ig. 3.3: Single phase two-wire line.<br />

The potential difference V 12 can be obtained in terms of q 1 and q 2 by using eqn. (3.5). Thus,<br />

V 12 =<br />

\ V 12 =<br />

1<br />

2pÎ<br />

1<br />

2pÎ<br />

2<br />

å<br />

q<br />

m<br />

o m = 1<br />

o<br />

L<br />

NM<br />

q<br />

1<br />

<br />

HG<br />

<br />

D2mI<br />

HG D1mKJ<br />

ln Volt<br />

I<br />

HG<br />

IO<br />

KJQP<br />

21<br />

22<br />

2<br />

11KJ<br />

12<br />

+<br />

D<br />

D<br />

ln q ln Volt ...(3.6)<br />

D<br />

D<br />

Since q 2 = –q 1 , D 21 = D 12 = D, D 11 = r 1 and D 22 = r 2<br />

V 12 =<br />

1<br />

2pÎ<br />

o<br />

L<br />

NM<br />

D r2<br />

q1<br />

ln - q1<br />

ln Volt<br />

r D<br />

\ V12 = 2q1D<br />

ln Volts<br />

2 rr<br />

\ C12 = q1<br />

pÎ o<br />

If r 1 = r 2 = r<br />

\ C 12 =<br />

1<br />

12<br />

p Îo<br />

=<br />

V D<br />

12 ln<br />

rr<br />

o<br />

I<br />

HG r KJ<br />

pÎ<br />

ln D<br />

12<br />

O Q P<br />

/m ...(3.7)<br />

/m ...(3.8)

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