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Electrical Power Systems

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292 <strong>Electrical</strong> <strong>Power</strong> <strong>Systems</strong><br />

angle (or clearing time) larger than this value, the system would be unstable. The maximum<br />

allowable value of the clearing angle and clearing time for the system to remain stable are<br />

known as critical clearing angle and critical clearing time respectively.<br />

rom ig. 11.11, d m = p – d 0, we have upon substitution into eqn. (11.49)<br />

cosd cr = cosd m + (d m – d 0 ) sind 0<br />

\ cosd cr = cosd m + (p – d 0 – d 0) sind 0<br />

\ cosd cr = cos (p – d 0) + (p – 2d 0) sind 0<br />

\<br />

cosd cr = (p – 2d 0 ) sind 0 – cosd 0<br />

\ d cr = cos –1 [(p – 2d 0) sind 0 – cosd 0] ...(11.53)<br />

Using eqn. (11.52), critical clearing time can be written as:<br />

t cr =<br />

d i ...(11.54)<br />

2H dcr – d0<br />

p fP<br />

i<br />

d cr can be computed using eqn.(11.53).<br />

Let us consider the double circuit line as shown in ig. 11.12. A three-phase short-circuit<br />

fault occurs on one of the line as shown in<br />

ig.11.12. Because of the rotor inertia,<br />

the power angle can not change instantly.<br />

Also, some power could still be<br />

transmitted during the fault because the<br />

terminal voltage of the generator will not<br />

be zero.<br />

ig. 11.12: Double circuit transmission line.<br />

ig. 11.13: Determination of d cr during fault conditions.<br />

In ig. 11.13, curve A before a fault, B during the fault and C after the fault–such that<br />

A = P max sind, B = K 1 A, and C = K 2 A with K 1

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