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Electrical Power Systems

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where J = moment of inertia of rotor (Kg–m 2 )<br />

But ws-elect = P w<br />

2<br />

w s-mech = synchronous speed in mechanical-rad/sec<br />

<strong>Power</strong> System Stability 277<br />

I s-mech HG KJ = rotor speed in electrical-radian/sec. ...(11.2)<br />

where P = number of poles of machine<br />

rom eqns.(11.1) and (11.2) we get<br />

L<br />

NM<br />

<br />

KE = 1 2<br />

J<br />

2 P<br />

\ KE = 1<br />

2 M w s-elect<br />

<br />

O<br />

QP<br />

2 I – 6<br />

. ws-elect ´ 10 . ws-elect<br />

HG KJ<br />

...(11.3)<br />

Where<br />

2<br />

2I<br />

M = J . ws-elect<br />

HG PKJ<br />

– 6<br />

´ 10 = moment of inertia in<br />

MJ-sec/elect-radian ...(11.4)<br />

We shall define the inertia constant H, such that<br />

GH = KE = 1<br />

2 M w s-elect MJ ...(11.5)<br />

Where G = three-phase MVA rating (base) of machine<br />

rom eqn. (11.5), we can write,<br />

H = inertia constant in MJ/MVA or MW-sec/MVA.<br />

M =<br />

2 GH<br />

w s-elect<br />

or M = GH<br />

180 f<br />

= 2 GH<br />

2 p f<br />

= GH<br />

p f<br />

M is also called the inertia constant.<br />

Assuming G as base, the inertia constant in per unit is<br />

MJ-sec/elect-radian ...(11.6)<br />

MJ-sec/elect-degree ...(11.7)<br />

M (pu) = H<br />

p f<br />

Sec2 /elect-radian ...(11.8)<br />

or M (pu) = H<br />

180 f<br />

Sec2 /elect-degree ...(11.9)

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