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Electrical Power Systems

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Optimal System Operation 423<br />

Now we will consider the transmission losses for determining l. One common practice is to<br />

express the total transmission loss as a quadratic function of the generator power outputs. The<br />

simplest quadratic form is<br />

m<br />

m<br />

PL = å å Pgi BijPgj ...(16.54)<br />

i=1 j=1<br />

Derivation of the loss formula is presented in next section.<br />

rom eqn . (16.30), we get,<br />

dC<br />

dP<br />

i<br />

gi<br />

+ l P<br />

P<br />

rom eqn. (16.54), we have<br />

P<br />

P<br />

L<br />

gi<br />

L<br />

gi<br />

= l, i = 1, 2, ..., m ...(16.55)<br />

m<br />

= 2å BijPgj ...(16.56)<br />

j=1<br />

rom eqns. (16.55) and (16.56), we get,<br />

bi + 2diPgi +<br />

2lå BijPgj = l<br />

m<br />

j=1<br />

m<br />

\ bi + 2diPgi + 2lBiiPgi + 2l<br />

j=1<br />

j¹ i<br />

å BijPgj = l<br />

At K-th iteration, eqn.(16.57) is expressed as:<br />

m<br />

å<br />

l-bi -2l<br />

BijPgj DPgi =<br />

j=1<br />

j¹ i<br />

2bdi + lBiig<br />

... (16.57)<br />

(K)<br />

Pgi =<br />

At K-th iteration, eqn.(16.23) is written as<br />

m<br />

(K)<br />

P (K)<br />

å gi = PD + PL i=1<br />

( K)<br />

i<br />

m<br />

( K)<br />

å<br />

j=1<br />

l -b -2l<br />

B P<br />

j¹ i<br />

(K) 2edi+ l Biij<br />

Substituting eqn. (16.58) in eqn. (16.59), we get,<br />

(K)<br />

ij gj<br />

...(16.58)<br />

...(16.59)

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