Electrical Power Systems

178 Electrical Power Systems
( 2)
Q3( cal )
= –0.314
\ ( 2)
DP = 0.319
2
L
NM
( 2)
DP = 0.0408
3
( 2)
DQ = 0.048
2
( 2)
DQ = –0.138
3
Dd
Dd
( 2)
2
( 2)
3
O
Q
P =
L
NM
52. 97 –31. 98
–31. 98 63. 48
O
QP
-1
( 2)
\ Dd2 = 0.0092 rad = 0.52°
( 2)
Dd = 0.00528 rad = 0.30°
3
L
NM
0. 3190
0. 0408
\ ( 3)
d = –0.0727 + 0.0092 = –0.0635 rad = –3.64°
2
L
NM
D|
V |
D|
V |
( 3)
d = –0.0582 + 0.00528 = –0.0529 rad = –3.03°
3
( )
2
( )
2
3 2
O
QP
=
L
NM
50. 97 –31. 98
–31. 98 60. 47
\ D|V 2| (2) = –0.0007
D|V 3| (2) = –0.00267
O
QP
-1
L
NM
0. 048
O
QP
–0. 138
\ |V 2 | (3) =|V 2 | (2) + D|V 2 | (2) = 0.9763 – 0.0007 = 0.9756
Example 7.5
( 0)
V2 ( 0)
d2
|V 3 | (3) =|V 3 | (2) + D|V 3 | (2) = 1.0 – 0.00267 = 0.9973
V1 = 10 . 0°
(slack bus)
| | = 10 .
= 00 .
UV|
W|
|V 3| = 1.0 PV bus
starting values
( 0)
d = 0.0} starting value
3
Y Bus matrix for this system:
Y Bus =
L
NM
26. 925 –68. 2° 1118 . 116. 6° 15. 81 108. 4°
1118 . 116. 6° 29. 065 - 63. 4° 17. 885 116. 6°
15. 81 108. 4° 17. 885 116. 6° 33. 615 –67. 2°
O
QP
O
QP