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Electrical Power Systems

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190 <strong>Electrical</strong> <strong>Power</strong> <strong>Systems</strong><br />

8.2 RATED MVA INTERRUPTING CAPACITY O A CIRCUIT BREAKER<br />

The circuit breakers rating requires the computation of rated momentary current and rated<br />

symmetrical interrupting current computation of symmetrical short circuit current requires<br />

subtransient reactances for synchronous machines. RMS value of momentary current is then<br />

computed by multiplying the symmetrical momentary current by a factor of 1.60 to consider the<br />

presence of DC off-set current.<br />

The interrupting current of a circuit breaker is inversely proportional to the operating<br />

voltage over a certain range, i.e.,<br />

I ov = I r ×<br />

V<br />

V<br />

r<br />

ov<br />

...(8.1)<br />

Where<br />

Iov = current at operating voltage<br />

Ir = current at rated voltage<br />

Vr = rated voltage<br />

Vov = operating voltage<br />

Note that operating voltage cannot exceed the maximum design value. Also rated interrupting<br />

current cannot exceed the rated maximum interrupting current.<br />

Therefore, three phase rated interrupting MVA capacity of a circuit breaker is given as<br />

where<br />

(MVA) rated-3f = 3 Vline ´ Iline<br />

...(8.2)<br />

r ric<br />

V line r = rated line voltage (kV)<br />

I line ric = rated interrupting current (KA)<br />

Thus, three phase short circuit MVA to be interrupted, where<br />

SC MVA (3f) = 3 Eo Isc × (MVA) Base ...(8.3)<br />

where<br />

|Eo| = prefault voltage (kV)<br />

|ISC| = short circuit current (KA)<br />

Note that MVArated–3f is to be more than or equal to the SC MVA (3f) required to be<br />

interrupted. A three phase fault which is very rare gives the highest short circuit MVA and a<br />

circuit breaker must be capable of interrupting it.<br />

Example 8.3: Three 11.2 KV generators are interconnected as shown in ig. 8.5 by a tie-bar<br />

through current limiting reactors. A three phase feeder is supplied from the bus bar of generator<br />

A at a line voltage 11.2 KV. Impedance of the feeder is (0.12 + j0.24) ohm per phase. Compute the<br />

maximum MVA that can be fed into a symmetrical short circuit at the far end of the<br />

feeder.

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