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Electrical Power Systems

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278 <strong>Electrical</strong> <strong>Power</strong> <strong>Systems</strong><br />

The range of inertia constants for certain machines are given in Table - 11.1<br />

Table 11.1: Typical Inertia Constants of Synchronous Machines<br />

Type of machine Inertia constant<br />

H (MJ/MVA.)<br />

Turbine generator:<br />

Condensing, 1800 rpm 9–6<br />

3600 rpm 7–4<br />

Noncondensing, 3600 rpm 4–3<br />

Waterwheel generator:<br />

Slow speed, < 200 rpm 2–3<br />

Hign speed, >200 rpm 2–4<br />

Synchronous Condenser:<br />

Large 1.25<br />

Small 1.0<br />

Synchronous motor with 2.0<br />

varies from 1.0 to 5.0<br />

and higher for heavy<br />

flywheels.<br />

* Where range is given, the first valve applies to machines of smaller MVA rating. [rom<br />

Weshting house <strong>Electrical</strong> Transmission and Distribution Reference Book, 1964, p. 486].<br />

ig. 11.1: low of powers in a synchronous generator.<br />

Consider a synchronous generator developing an electromagnetic torque Te (and a<br />

corresponding electromagnetic power Pe ) while operating at the synchronous speed ws . If the<br />

input torque provided by the prime mover, at the generater shaft is Ti , then under steady-state<br />

conditions (i.e., without any disturbance)<br />

Te = Ti ...(11.10)<br />

Here we have neglected any retarding torque due to rotatianal losses. Therefore we have<br />

Te ws = Ti ws ...(11.11)<br />

and Ti ws – Te ws = Pi – Pe = 0 ...(11.12)<br />

If there is a departure from steady-state occurs, for example, a change in load or a fault,<br />

then input power Pi is not equal to Pe , if the armature resistance is neglected. Therefore<br />

left-side of eqn. (11.12) is not zero and an accelerating torque comes into play. If Pa is the<br />

corresponding accelerating (or decelerating) power, then

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