Electrical Power Systems

352 Electrical Power Systems
ig. 13.6(h): DP g4(pu Mw) vs. time (sec).
ig. 13.6: Dynamic responses for Case-2.
=(cpf 13 + cpf 23 ) DPL 3 + (cpf 14 + cpf 24 ) DPL 4
– (cpf 31 + cpf 41) DPL 1 – (cpf 32 + cpf 42) DPL 2
= (0 + 0) ´ 0.04 + (0.30 + 0.0) × 0.04 – (0 + 0.3) × 0.04
– (0.25 + 0.25) × 0.04
= – 0.02 pu MW.
igure 13.6 shows the dynamic responses. igure 13.6(c) shows the actual power on the tieline.
It is to be observed that it settles to –0.02 pu MW, which is scheduled power flow on the
tie-line in the steady-state.
As given by eqn. (13.8), in the steady state, the GENCOs must generate
DP g1, steady-state = DP 1 = 0.5 ´ 0.04 + 0.25 × 0.04 + 0.0 + 0.3 × 0.04
= 0.042 pu MW
and Similarly,
DPg2, steady - state = DP2 = 0.018 pu MW
DP g3, steady - state = DP 3 = 0.078 pu MW
DP g4 , steady - state = DP 4 = 0.022 pu MW
ig. 13.7(a): D 1 (Hz) vs. time (sec).