12.07.2015 Views

chemical thermodynamics of neptunium and plutonium - U.S. ...

chemical thermodynamics of neptunium and plutonium - U.S. ...

chemical thermodynamics of neptunium and plutonium - U.S. ...

SHOW MORE
SHOW LESS
  • No tags were found...

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

306 16. Plutonium aqua ionsE ◦ = (0.954 ± 0.010) V by applying the SIT to data from cyclic voltammetrymeasurements at 0.5, 1, 2, <strong>and</strong> 3 M ionic strengths. Rai [84RAI] reported E ◦= (0.956 ± 0.025) V from solubility measurements. Capdevila’s value <strong>of</strong> E ◦ =(0.938 ± 0.010) V was also derived by applying the SIT treatment to their data.They calculated the ion interaction parameter ε = (0.22 ± 0.03) kg·mol −1(similar to the values for the reactions involving the corresponding uranium <strong>and</strong><strong>neptunium</strong> species (Appendix B)). Although these three values for the st<strong>and</strong>ardpotential lie within their combined uncertainties, we do not select the data becausethe measurements <strong>of</strong> Riglet, Robouch <strong>and</strong> Vitorge were hampered by experimentalproblems (cf. Appendix A) as was pointed out in a later publication [95CAP/VIT]by one co-author <strong>of</strong> the initial investigation. Rai’s value was derived solely fromsolubility measurements <strong>and</strong> carries, therefore, the large uncertainty <strong>of</strong> 0.025 V.Because the value <strong>of</strong> Capdevila et al. also has a relatively large uncertainty <strong>of</strong> 0.010 V,we derive the formal potential E ◦′ (16.7, 1MHClO 4 , 298.15 K) =(0.913±0.005) V,log 10 K(16.7, 1MHClO 4 , 298.15 K) = (15.43 ± 0.08) <strong>and</strong> r G m (16.7, 1MHClO 4 ,298.15 K) =−(88.09 ± 0.48) kJ·mol −1 by combining the raw data <strong>of</strong> Capdevila <strong>and</strong>Vitorge [95CAP/VIT] <strong>and</strong> Rabideau [56RAB]. These data are corrected to st<strong>and</strong>ardconditions using the SIT ε (= (0.22 ± 0.03) kg·mol −1 ) value <strong>of</strong> Capdevila <strong>and</strong>Vitorge [95CAP/VIT]. The following values are obtained:for the reactionE ◦ (16.7, 298.15 K) = (0.936 ± 0.005) Vlog 10 K ◦ (16.8, 298.15 K) = (15.82 ± 0.09) r G ◦ m (16.8, 298.15 K) = −(90.29 ± 0.51) kJ·mol−1PuO 2+2+ 1 2 H 2(g) Å PuO + 2 + H+ (16.8)The correction to the st<strong>and</strong>ard pressure <strong>of</strong> 1 bar lies within the uncertainty <strong>of</strong> thevalues. The estimate <strong>of</strong> Fuger <strong>and</strong> Oetting [76FUG/OET], E ◦ = (1.016 ± 0.05) V, appearsto be too high in light <strong>of</strong> these results, <strong>and</strong> the less positive value, E ◦ = 0.936 V,is used here. Therefore, f G ◦ m (PuO+ 2, aq, 298.15 K) = −(852.6 ± 2.9) kJ·mol−1is derived from r G ◦ m (16.8, 298.15 K) <strong>and</strong> the selected value <strong>of</strong> fG ◦ m (PuO2+ 2 ,aq,298.15 K).The change in enthalpy for Reaction (16.8) is obtained from the temperature coefficient<strong>of</strong> the potential. Figure 16.1 shows the temperature variation <strong>of</strong> the derivative withrespect to temperature <strong>of</strong> the PuO 2+2 /PuO+ 2 couple formal potential (1.0 M HClO 4)forRabideau’s [56RAB] <strong>and</strong> Capdevila <strong>and</strong> Vitorge’s [95CAP/VIT] data. Because <strong>of</strong> theconflicts in the trends in temperature variation, (∂ E ◦′ /∂T )=(0.0000±0.0002) V·K −1is selected by this review. This is consistent with the variation <strong>of</strong> the temperature coefficientbetween the different investigators listed in Table 16.2. Rabideau [56RAB]reported a very small negative coefficient, whereas Capdevila <strong>and</strong> Vitorge, as well as

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!