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chemical thermodynamics of neptunium and plutonium - U.S. ...

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16.5 Pu 3+ 31316.5 Pu 3+The values <strong>of</strong> the st<strong>and</strong>ard molar enthalpy <strong>of</strong> formation, the Gibbs energy <strong>of</strong> formation,<strong>and</strong> the molar entropy <strong>of</strong> the <strong>plutonium</strong>(III) cation were very thoroughly reviewedby Fuger <strong>and</strong> Oetting [76FUG/OET]. Their selected value f H ◦ m (Pu3+ ,aq,298.15 K) = −(592.0 ± 2.1) kJ·mol −1 , was derived from calorimetric measurements<strong>of</strong> the enthalpies <strong>of</strong> solution <strong>of</strong> Pu <strong>and</strong> PuCl 3 (cr) in HCl(aq) [76FUG/OET]. Theiranalysis used the value <strong>of</strong> Robinson <strong>and</strong> Westrum [49ROB/WES] for the enthalpy <strong>of</strong>solution <strong>of</strong> PuCl 3 (cr) in 6 M HCl(aq)(−(92.68 ± 0.42) kJ·mol −1 ) <strong>and</strong> the result <strong>of</strong>the extrapolation <strong>of</strong> the enthalpy <strong>of</strong> solution <strong>of</strong> PuCl 3 (cr) in HCl(aq) to infinite dilution(−(133.47 ± 0.84) kJ·mol −1 ) by the same authors. For the enthalpy <strong>of</strong> solution <strong>of</strong>Pu(cr,α) in 6 M HCl(aq) Akhachinskij’s [66AKH] value <strong>of</strong> −(592.04±1.67) kJ·mol −1was accepted. Using revised auxiliary data (cf. Section 18.1), f H ◦ m (Pu3+ , aq, 298.15 K) = −(591.8 ± 2.0) kJ·mol −1Based on the Gibbs energy <strong>and</strong> enthalpy values for the dissolution reaction,PuCl 3·6H 2 O(cr) → Pu 3+ + 3Cl − + 6H 2 O(l) (16.13)(−(30.125 ± 0.840) kJ·mol −1 <strong>and</strong> −(34.60 ± 0.64) kJ·mol −1 , as discussed inSections 18.1.3.3.a <strong>and</strong> 18.1.3.3.b), r Sm ◦ (16.13 ) =−(15.01 ± 3.53) J·K−1·mol−1 .From this value <strong>and</strong> using new CODATA auxiliary data <strong>and</strong> values fromthis review for Sm ◦ (Cl− , aq, 298.15 K) = (56.60 ± 0.20) J·K −1·mol−1 <strong>and</strong>Sm ◦ (PuCl 3·6H 2 O, cr, 298.15 K) = (420 ± 5) J·K −1·mol−1 , cf. Section 18.1.3.3,S ◦ m (Pu3+ , aq, 298.15 K) =−(184.5 ± 6.2) J·K −1·mol −1 .Then, using S ◦ m (Pu, cr, 298.15 K)= (54.46 ± 0.80) J·K−1·mol −1 as selected bythis review (cf. Section 15.1.2), r S ◦ m (16.14 )= −(42.95 ± 6.21) J·K−1·mol −1 wascalculated.α-Pu + 3H + Å Pu 3+ + 3 2 H 2(g) (16.14)From this <strong>and</strong> the selected value <strong>of</strong> f Hm ◦ , the selected value f G ◦ m (Pu3+ , aq, 298.15 K) = −(579.0 ± 2.7) kJ·mol −1is calculated. The st<strong>and</strong>ard potential for the α-Pu/Pu 3+ couple, E ◦ (16.15),is then calculated asPu 3+ (aq) + 3e − = α-Pu (16.15)E ◦ (16.15) = −(2.000 ± 0.009) V.For the value <strong>of</strong> the Pu(VI)/Pu(III) redox couple, Capdevila [92CAP, 92CAP/VIT,95CAP/VIT] obtained E ◦′ (16.6, 1MHClO 4 ) = (1.013 ± 0.017) V from K (16.5), <strong>and</strong>

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