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chemical thermodynamics of neptunium and plutonium - U.S. ...

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A. Discussion <strong>of</strong> selected references 787Table A.30: Formal potentials for the Np(V)/Np(IV) couple in Na 2 CO 3 (aq) solutionsas calculated from values in [96DEL/VIT].[Na 2 CO 3 ]E ′ ◦0 E ′ ◦1 E ′ ◦2 E ′ ◦3(mol·dm −3 )0.3 0.661 0.641 0.693 0.6730.6 0.648 0.694 0.651 0.6961.0 0.658 0.641 0.552 0.535 (a)1.5 0.642 0.620 0.819 0.7980 (0.538 ± 0.020) (0.553 ± 0.058) (0.480 ± 0.266) (0.494 ± 0.268)1.0 (b) 0.514 (b)ε(A.77) (0.361 ± 0.176) (0.535 ± 0.501) (a) −(0.472 ± 2.296) −(0.298 ± 2.317)(kg·mol −1 )ε (Na + ,Np(CO 3 ) 6−5 ) −(0.173 ± 0.223) (0.001 ± 0.519) −(1.006 ± 2.301) −(0.832 ± 2.321)(kg·mol −1 )(a) used in this review(b) [79FED/PER]Table A.30. From these various possible formal potentials, the st<strong>and</strong>ard potential<strong>of</strong> the NpO + 2 /Np4+ redox couple, the values corrected to the aqueous media for theformation constant <strong>of</strong> the Np(V) limiting complex, <strong>and</strong> the value <strong>of</strong> the p CO2 /[CO 2−3 ]equilibrium constant selected in this review, values <strong>of</strong> the formation constant <strong>of</strong> theNp(IV) limiting complexNp 4+ + 5CO 2−3Å Np(CO 3 ) 6−5(A.78)β 5(IV) (A.78) = [Np(CO 3) 6−5 ]a Np 4+[CO 2−3 ]5were calculated (where a Np 4+ is in molal units, while the concentrations are in molarunits). Extrapolation to zero ionic strength was done by linear regression.The influence <strong>of</strong> the [Np(V)]/[Np(IV)] ratio is usually smaller than the uncertainty.As expected, using the measured pH values does not remove the scatter in the data,especially if the sole value measured following electrolysis is used along with valuesmeasured before electrolysis. For this reason, the only reliable ionic strength correctionsare those calculated assuming equilibrium with the air. The st<strong>and</strong>ard potentialis (88 ± 58) mV lower than the formal potential in 1.0 M Na 2 CO 3 , from whichit is deduced (corresponding to (2.98 ± 1.02) in log 10 β 5(IV) ). From the ε valuederived from this extrapolation to zero ionic strength, ε (Na + ,Np(CO 3 ) 6−5 ) = (0.00 ±0.52)kg·mol −1 is calculated. Assuming equilibrium with the air, recalculation resultsin the value log 10 β 5(IV) (1.0 MNa 2 CO 3 , A.78) = 43.93, while 42.13 is calculated usingthe (only) solution for which the pH was measured at the end <strong>of</strong> the electrolysis.This last value is consistent with Fedoseev, Peretrukhin <strong>and</strong> Krot’s value, 41.79, recal-

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