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chemical thermodynamics of neptunium and plutonium - U.S. ...

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622 A. Discussion <strong>of</strong> selected references[69MET/GUI]This is a solvent extraction study <strong>of</strong> the hydrolysis <strong>of</strong> Pu(IV) for an aqueous medium<strong>of</strong> ionic strength 1.0 M (H/LiClO 4 ). No values for the hydrolysis constants are derivedin this paper.[69MOS]This publication is a compilation <strong>of</strong> stability constants <strong>of</strong> actinide complexes with variouslig<strong>and</strong>s. Values for nitrate, sulphate, carbonate <strong>and</strong> phosphate complexes, as determinedin previous work, published <strong>and</strong> unpublished, were reported together withthe author’s estimates. For the phosphate system, constants for Np(III) complexes withH 2 PO − 4were included, estimated on the basis <strong>of</strong> the results for Pu(III), Am(III) <strong>and</strong>Cm(III) published in a later paper [71MOS4]Np 3+ + nH 2 PO − 4Å Np(H 2 PO 4 ) 3−nn(A.35)log 10 β n (A.35, n = 1, unreported temperature, I → 0) = 2.40log 10 β n (A.35, n = 2, unreported temperature, I → 0) = 3.73log 10 β n (A.35, n = 3, unreported temperature, I → 0) = 5.64log 10 β n (A.35, n = 4, unreported temperature, I → 0) = 6.2<strong>and</strong> estimates at I = 0 for the Pu(III) constants later reported in [71MOS4]:Pu 3+ + nH 2 PO − 4Å Pu(H 2 PO 4 ) 3−nn(A.36)log 10 β n (A.36, n = 1, unreported temperature, I → 0) = 2.39log 10 β n (A.36, n = 2, unreported temperature, I → 0) = 3.70log 10 β n (A.36, n = 3, unreported temperature, I → 0) = 5.63log 10 β n (A.36, n = 4, unreported temperature, I → 0) = 6.2Since the experimentally determined constants for the Pu(III) in [71MOS4] have beenrejected in the present review, the same holds for the corresponding Np(III) complexes.Moskvin includes also constants for complexes <strong>of</strong> Np(VI) with both H 2 PO − 4<strong>and</strong> HPO 2−4<strong>and</strong> for Pu(VI) with HPO 2−4, reported to have been obtained in a solventextraction study at an ionic strength 0.5 M.NpO 2+2+ H 2 PO − 4Å NpO 2 H 2 PO + 4(A.37)log 10 β(A.37, unreported temperature, I = 0.5M) = 1.70log 10 β(A.37, unreported temperature, I → 0) = 2.33NpO 2+2+ HPO 2−4Å NpO 2 HPO 4 (aq) (A.38)

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