On the Flavor Problem in Strongly Coupled Theories - THEP Mainz
On the Flavor Problem in Strongly Coupled Theories - THEP Mainz
On the Flavor Problem in Strongly Coupled Theories - THEP Mainz
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68 Chapter 2. The Randall Sundrum Model and its Holographic Interpretation<br />
(2.90) holds and <strong>the</strong> BCs become<br />
∂t χ a n(ɛ + ) = 0 , (2.102)<br />
∂t χ a n(1 − ) = − L<br />
2πrc<br />
M 2 a<br />
M 2 KK<br />
χ a n(1 − ) = −L v2 4g2 4<br />
4M 2 χ<br />
KK<br />
a n(1 − ) = −L m2a M 2 χ<br />
KK<br />
a n(1 − ) ,<br />
where <strong>the</strong> masses of <strong>the</strong> zero modes ma, with a = W, Z have been <strong>in</strong>troduced. By<br />
comparison with (2.93), <strong>the</strong> propagator can be found from (2.82), and reads<br />
rcD ξ µν(q, t; t ′ �<br />
1 L � 2<br />
) = ηµν + t< − t 2 − t ′2 + 1 ��<br />
+ O(q 2 ) , (2.103)<br />
2πm 2 W.Z<br />
4π M 2 KK<br />
and <strong>the</strong> propagator for <strong>the</strong> photon is given by (2.86).<br />
The 4D effective <strong>the</strong>ory is constructed by <strong>in</strong>sert<strong>in</strong>g <strong>the</strong> KK decomposition (2.99) <strong>in</strong>to<br />
(2.98), apply<strong>in</strong>g <strong>the</strong> EOM and <strong>the</strong> orthonormality relation, so that after <strong>in</strong>tegrat<strong>in</strong>g<br />
out <strong>the</strong> fifth dimension one ends up with<br />
SGauge,2 = �<br />
�<br />
n<br />
d 4 �<br />
x − 1 (n)<br />
F µν F<br />
4 µν(n) − 1<br />
2ξ<br />
− 1<br />
4 Z(n) µν Z µν(n) − 1<br />
2ξ<br />
�<br />
− 1 +(n)<br />
W µν W<br />
2 −µν(n) − 1<br />
∂ µ Z (n)<br />
µ<br />
� 2<br />
ξ ∂µ W +(n)<br />
µ<br />
�<br />
∂ µ A (n)<br />
µ<br />
+ (mZ n ) 2<br />
2<br />
+ 1 (n)<br />
∂µϕ A 2 ∂µ ϕ (n)<br />
A − ξ(mAn ) 2<br />
ϕ<br />
2<br />
(n)<br />
A ϕ(n)<br />
A<br />
∂ ν W −(n)<br />
ν<br />
+ ∂µϕ +(n)<br />
W ∂µ ϕ −(n)<br />
W − ξ(mWn ) 2 ϕ +(n)<br />
W ϕ−(n)<br />
W<br />
� 2<br />
+ (mAn ) 2<br />
2 A(n) µ A µ(n)<br />
Z (n)<br />
µ Z µ(n)<br />
+ (m W n ) 2 W +(n)<br />
µ W −µ(n)<br />
1 (n)<br />
+ ∂µϕ ϕ<br />
2 2<br />
(n)<br />
Z ϕ(n)<br />
Z<br />
� �<br />
+ d 4 �<br />
1<br />
x<br />
2 ∂µh∂ µ h − λv 2 h 2<br />
�<br />
,<br />
Z ∂µ ϕ (n)<br />
Z − ξ(mZn ) 2<br />
(2.104)<br />
under <strong>the</strong> additional condition, that <strong>the</strong> Fourier coefficients <strong>in</strong> (2.99) and (2.100) are<br />
a a n = − 1<br />
ma , b<br />
n<br />
a n = Ma<br />
√r<br />
χ a n(1 − )<br />
m a n<br />
. (2.105)<br />
Solv<strong>in</strong>g <strong>the</strong> EOM with <strong>the</strong> BCs (2.102) leads to<br />
χ a �<br />
L<br />
n(t) = Nn<br />
π t c+ n (t) , (2.106)<br />
where only <strong>the</strong> UV BC is used <strong>in</strong> determ<strong>in</strong><strong>in</strong>g <strong>the</strong> unspecified coefficient <strong>in</strong> <strong>the</strong> homogeneous<br />
solution, so that<br />
c + n (t) = Y0(x a nɛ) J1(x a nt) − J0(x a nɛ) Y1(x a nt) , (2.107)<br />
c − n (t) = 1<br />
xa d � +<br />
t c n (t)<br />
nt dt<br />
� = Y0(x a nɛ) J0(x a nt) − J0(x a nɛ) Y0(x a nt) . (2.108)