06.06.2022 Views

B. P. Lathi, Zhi Ding - Modern Digital and Analog Communication Systems-Oxford University Press (2009)

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

280 SAMPLING AND ANALOG-TO-DIGITAL CONVERSION

Example 6.3 A signal m(t) of bandwidth B = 4 kHz is transmitted using a binary companded PCM with

µ = 100. Compare the case of L = 64 with the case of L = 256 from the point of view of

transmission bandwidth and the output SNR.

For L = 64, n = 6, and the transmission bandwidth is nB = 24 kHz,

So

- =(a+ 36) dB

No

a= lO !og [ln (l0l)] 2 = -8.51

Hence,

So

= 27.49 dB

No

For L = 256, n = 8, and the transmission bandwidth is 32 kHz,

So

- = a + 6n = 39.49 dB

No

The difference between the two SNRs is 12 dB, which is a ratio of 16. Thus, the SNR

for L = 256 is 16 times the SNR for L = 64. The former requires just about 33% more

bandwidth compared to the latter.

Comments on Logarithmic Units

Logarithmic units and logarithmic scales are very convenient when a variable has a large

dynamic range. Such is the case with frequency variables or SNRs. A logarithmic unit for the

power ratio is the decibel (dB), defined as 10 log 10 (power ratio). Thus, an SNR is x dB, where

s

x = 10 log 10 N

We use the same unit to express power gain or loss over a certain transmission medium. For

instance, if over a certain cable the signal power is attenuated by a factor of 15, the cable gain is

1

G = 10 log 10 15

= - 11.76 dB

or the cable attenuation (loss) is 1 1.76 dB.

Although the decibel is a measure of power ratios, it is often used as a measure of power

itself. For instance, "100 watt" may be considered to be a power ratio of 100 with respect to

1-watt power, and is expressed in units of dBW as

PctBW = 10 log 10 100 = 20 dBW

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!