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B. P. Lathi, Zhi Ding - Modern Digital and Analog Communication Systems-Oxford University Press (2009)

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7.9 MAry Digital Carrier Modulation 381

design a frequency increment 8f and let

fm =Ji + (m - 1)8f

m = I, 2, ... , M

For this FSK with equal frequency separation, the frequency deviation (in analyzing the FM

signal) is

!::,.f = fM - f1 = ( M - 1)8f

2 2

It is therefore clear that the selection of the frequency set {Ii} determines the performance and

the bandwidth of the FSK modulation. If 8f is chosen too large, then the M-ary FSK will use

too much bandwidth. On the other hand, if 8f is chosen too small, then over the time interval

of T b second, different FSK symbols will show virtually no difference and the receiver will be

unable to distinguish the different symbols reliably. Thus large 8f leads to bandwidth waste,

whereas small 8f is prone to detection error due to transmission noise and interference.

The task of M-ary FSK design is to determine a small enough 8f that each FSK symbol

A cos Wit is highly distinct from all other FSK symbols. One solution to this problem

of FSK signal design actually can be found in the discussion of orthogonal signal space in

Sec. 2.6.2. If we can design FSK symbols to be orthogonal in T b by selecting a small 8f

(or !::,.f), then the FSK signals will be truly distinct over T b , and the bandwidth consumption

will be small.

To find the minimum 8f that leads to an orthogonal set of FSK signals, the orthogonality

condition according to Sec. 2.6.2 requires that

{Tb

J o A cos (2nf mt) A cos (2nfnt) dt = 0 m-:/= n (7.62)

We can use this requirement to find the minimum 8f. First of all,

Since in practical modulations, if m + fn)T b is very large (often no smaller than 10 3 ), the first

term in Eq. (7.63) is effectively zero and negligible. Thus, the orthogonality condition reduces

to the requirement that for any integer m -f= n,

Because fm = !1 + (m - 1)8f, for mutual orthogonality we have

sin [2n(m - n)8fTb] = 0

m -:/= n

From this requirement, it is therefore clear that the smallest 8f to satisfy the mutual

orthogonality condition is

8f = - Hz

2T b

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